iOS 中字符串不会进行 url 编码

发布于 2025-01-03 06:38:09 字数 422 浏览 2 评论 0原文

我真的是脑子里放屁了，但是我不明白为什么这不是为我的生活进行编码。一直在寻找，我什至无法获得要编码的代码示例。有什么想法吗？

NSString *searchString = @"waffl&es";

NSString *encodedSearchString = [searchString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *urlString = [NSString stringWithFormat:@"http://en.wikipedia.org/?search=%@", encodedSearchString];
NSURL *url = [NSURL URLWithString:urlString];

原文

I'm seriously having a brain fart here, but I can't figure out why this isn't encoding for the life of me. Been searching all over, and I can't even get the code samples to encode. Any ideas?

NSString *searchString = @"waffl&es";

NSString *encodedSearchString = [searchString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *urlString = [NSString stringWithFormat:@"http://en.wikipedia.org/?search=%@", encodedSearchString];
NSURL *url = [NSURL URLWithString:urlString];

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

爱人如己 2025-01-10 06:38:09

为了将来的参考，这就是我发现的工作原理（即正确编码所有内容）

+ (NSString*)encodeURL:(NSString *)string
{
    NSString *newString = (__bridge_transfer NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (__bridge CFStringRef)string, NULL, CFSTR(":/?#[]@!$ &'()*+,;=\"<>%{}|\\^~`"), CFStringConvertNSStringEncodingToEncoding(NSUTF8StringEncoding));

    if (newString) 
    {
        return newString;
    }

    return @"";
}

For future reference, this is what I found to work (i.e. encode everything properly)

+ (NSString*)encodeURL:(NSString *)string
{
    NSString *newString = (__bridge_transfer NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (__bridge CFStringRef)string, NULL, CFSTR(":/?#[]@!$ &'()*+,;=\"<>%{}|\\^~`"), CFStringConvertNSStringEncodingToEncoding(NSUTF8StringEncoding));

    if (newString) 
    {
        return newString;
    }

    return @"";
}

回复收藏 0 原文

~没有更多了~