在脚本中将文件移动到具有相似名称的目录
我有一个目录，其中包含子目录和文件，其名称以类似于子目录的字符串开头；例如
bar/
foo-1/ (dir)
foo-1-001.txt
foo-1-002.txt
foo-1-003.txt
foo-2/ (dir)
foo-2-001.txt
foo-2-002.txt
foo-2-003.txt
foo-3/ (dir)
foo-3-001.txt
foo-3-002.txt
foo-3-003.txt
等等
所有文件当前都处于同一级别。我想使用脚本将相应的 .txt 文件移动到其名称相似的目录中（在我当前的情况下有 > 9500 个）。
我写了以下内容，但我遗漏了一些东西，因为我无法移动文件。
#!/bin/sh
# directory basename processing for derivatives
# create directory list in a text file
find ./ -type d > directoryList.txt
# setup while loop for moving text files around
FILE="directoryList.txt"
exec 3<&0
exec 0<$FILE
while read line
do
echo "This is a directory:`basename $line`"
filemoves=`find ./ -type f -name '*.txt' \! -name 'directoryList.txt' | sed 's|-[0-9]\{3\}\.txt$||g'`
if [ "`basename $filemoves`" == "$line" ]
then
cp $filemoves $line/
echo "copied $filemoves to $line"
fi
done
exec 0<&3
在我到达 if 之前，一切似乎都正常。我正在处理许多 *nix，所以我必须小心我所抛出的论点（RHEL、FreeBSD，可能还有 Mac OS X）。
I have a directory with sub-directories and files with names that start with a string similar to the sub-directories; e.g.
bar/
foo-1/ (dir)
foo-1-001.txt
foo-1-002.txt
foo-1-003.txt
foo-2/ (dir)
foo-2-001.txt
foo-2-002.txt
foo-2-003.txt
foo-3/ (dir)
foo-3-001.txt
foo-3-002.txt
foo-3-003.txt
etc.
All files are currently at the same level. I'd like to move the corresponding .txt files into their similarly-named directories with a script (there are > 9500 in my current situation).
I've written the following, but I'm missing something, as I can't get the files to move.
#!/bin/sh
# directory basename processing for derivatives
# create directory list in a text file
find ./ -type d > directoryList.txt
# setup while loop for moving text files around
FILE="directoryList.txt"
exec 3<&0
exec 0<$FILE
while read line
do
echo "This is a directory:`basename $line`"
filemoves=`find ./ -type f -name '*.txt' \! -name 'directoryList.txt' | sed 's|-[0-9]\{3\}\.txt$||g'`
if [ "`basename $filemoves`" == "$line" ]
then
cp $filemoves $line/
echo "copied $filemoves to $line"
fi
done
exec 0<&3
Things seem to work OK until I get to the if. I'm working across a number of *nix, so I have to be careful what arguments I'm throwing around (RHEL, FreeBSD, and possibly Mac OS X, too).
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假设您的文件确实与上面的模式匹配（最后一个破折号之前的所有内容都是目录名称），这应该可以做到：
如果它告诉您命令行太长（将 *.txt 扩展到 4900 个文件很多），请尝试以下操作：
Assuming your files really match the pattern above (everything before the last dash is the directory name) this should do it:
and if it tells you command line too long (expanding *.txt into 4900 files is a lot) try this:
我不是 shell 脚本专家，但我知道在许多 shell 中（根据互联网上的此页面： http://www.vectorsite.net/tsshell.html 这包括 SH)，字符串比较是使用“=”运算符而不是“==”完成的。
I'm not a shell script expert but I'm aware that in many shells (and according to this page on the internet: http://www.vectorsite.net/tsshell.html this includes SH), string comparison is done with the "=" operator, not "==".
[代码块已删除]
原因 1. 使用
ls而不是通配符原因 2. 使用
mv $VAR1 $VAR2样式移动而不引用变量[code block removed]
Reason 1. Used
lsinstead of globbingReason 2. Used
mv $VAR1 $VAR2style moving without quoting variables