为什么我的正交投影矩阵不起作用？
我正在尝试使用正交投影渲染位于平面 (z=0) 中的一些四边形。在阅读正交投影矩阵的公式？后，我确实设置了投影矩阵？但我想我做错了什么。
我的第一次尝试是以下矩阵。 W 和 H 是我所需视口的宽度和高度，在以下示例中为 640x640：
˹ 2/w 0 0 0 ˺
| 0 2/h 0 0 |
| 0 0 0 0 |
˻ 0 0 0 1 ˼
这是我渲染左上角位于 (0,0,0) 的四边形时获得的结果：
因为它是垂直翻转的，所以我将矩阵更改为：
˹ 2/w 0 0 0 ˺
| 0 -2/h 0 0 |
| 0 0 0 0 |
˻ 0 0 0 1 ˼
我得到：
然后我尝试移动我的四边形，结果出乎意料。我希望 3D 空间的 X 和 Y 与视口的 X 和 Y 相匹配。然而，当我沿 X 轴移动四边形时，发生了以下情况：
沿 Y 轴移动同样产生了意想不到的结果：
如何修复矩阵，使 3D 空间的 X 轴和 Y 轴与视口的 X 轴和 Y 轴匹配？非常感谢。
I am trying to render some quads that are located in the plane (z=0) with an orthogonal projection. I did set up a projection matrix after reading Formula for a orthogonal projection matrix? but I think I did something wrong.
My first attempt was the following matrix. W, and H are the width and height of my desired viewport which is 640x640 in the following examples :
˹ 2/w 0 0 0 ˺
| 0 2/h 0 0 |
| 0 0 0 0 |
˻ 0 0 0 1 ˼
Here is what I obtained when I rendered a quad whose topleft corner was in (0,0,0) :
Since it was flipped vertically I changed my matrix to :
˹ 2/w 0 0 0 ˺
| 0 -2/h 0 0 |
| 0 0 0 0 |
˻ 0 0 0 1 ˼
I obtained :
Then I tried to move my quad around and the results were unexpected. I wanted the X and Y of the 3D space to match those of the viewport. However here is what happened when I moved the quad along the X axis :
Moving along the Y axis gave equally unexpected results :
How can I fix my matrix so that the X and Y axis of the 3D space match those of the viewport ? Many thanks in advance.
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这个投影矩阵实际上是正确的。问题出在四元转换代码中，抱歉弄乱了。
This projection matrix is actually correct. The problem was in the quad translation code, sorry for messing up.
你错过了远近剪辑。试试这个
You missing the far near clipping. Try this