将 NSDate 转换为字符串时出现问题

发布于 2025-01-02 14:42:04 字数 637 浏览 1 评论 0原文

这个极其简单的任务显然非常困难...

NSDate *date;
date = [someMethod here];
//I've checked with debugger that the method returns an object of type NSDate. 
//The description of date at this point is: "2012-02-02 19:42:00 +0000"

NSDateFormatter *dateFormat;
[dateFormat setDateFormat:@"dd-MM-yy hh:mm"];
NSString *dateString = [dateFormat stringFromDate:date];

dateString is just NIL

有谁知道出了什么问题吗？

编辑：我真正想要实现的目标很简单：

NSString *receivedDate = @"2012-02-02T20:42:00+01:00";
NSString *fixedDate = [do some magic]
//value of fixedDate is now: "02-02-12 20:42"

原文

This extremely simple task was apparantly very hard...

NSDate *date;
date = [someMethod here];
//I've checked with debugger that the method returns an object of type NSDate. 
//The description of date at this point is: "2012-02-02 19:42:00 +0000"

NSDateFormatter *dateFormat;
[dateFormat setDateFormat:@"dd-MM-yy hh:mm"];
NSString *dateString = [dateFormat stringFromDate:date];

dateString is just NIL

Does anyone know what's wrong?

Edit: What i really want to achieve is simply:

NSString *receivedDate = @"2012-02-02T20:42:00+01:00";
NSString *fixedDate = [do some magic]
//value of fixedDate is now: "02-02-12 20:42"

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你是我的挚爱i 2025-01-09 14:42:04

正如安娜所说，你需要分配一个 NSDateFormatter 实例，因为你得到的只是一个 NULL ptr，它只是忽略消息 setDateFormat 和 stringFromDate，让你得到 NULL。

但您的小时格式也不正确。请参阅日期格式化程序参考

这对我有用：

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@@"dd-MM-yy HH:mm"];
NSString *dateString = [df stringFromDate:date];

As Anna said you need to allocate an instance of NSDateFormatter because all you get is a NULL ptr, which just ignores the messages setDateFormat and stringFromDate, leaving you with NULL.

But also your format is for hours is incorrect. Refer to Date Formatter reference

This works for me:

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@@"dd-MM-yy HH:mm"];
NSString *dateString = [df stringFromDate:date];

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