如何列出要“记录”的社区Liferay 6 中的用户？

Question

我正在尝试创建一个社区选择框，使访问者能够跳转到打开的 Liferay 社区。然而，它似乎只适用于经过身份验证的用户。那么我如何向所有用户（包括注销的用户）列出“开放”社区？

这是我当前的代码

#set ($myPlaces = $user.getMyPlaces())
    #if($listTool.size($myPlaces) > 0)

        <select id="communitySelector">

        #foreach ($myPlace IN $myPlaces)
            #if ($myPlace.isCommunity())

                #set ($myPlaceURL = ${myPlace.getFriendlyURL()})
                ## Only link if theres pages
                #if ($myPlace.hasPublicLayouts())
                    ## Prefix web for 'public'
                   #set ($myPlaceURL = "${public_pages_url}${myPlaceURL}")

                   ## Select if current community
                     #set($commSelected = "")
                    #if($themeDisplay.getLayout().getGroup().getName() == $myPlace.getName())
                        #set($commSelected = " selected='selected' ")
                    #end
                    <option $commSelected value="${portal_url}${myPlaceURL.toString()}">$myPlace.getName()</option>


               #end

            #end
        #end
            </select>
    #end

Answer 1

按照回答我自己的 Liferay 问题的悠久传统，这里是我想出的解决方案的代码片段，用于向所有用户（包括公共/来宾注销用户）列出社区

  ## Grab this service as MyPlaces only available to authenticated users
  #set($groupLocalService =  $serviceLocator.findService("com.liferay.portal.service.GroupLocalService"))

  ## Get all Groups
  #set($groupList = $groupLocalService.getGroups(-1, -1))

  ## Grab all groups that are Communities
  #set($commList = [])
  #foreach($group in $groupList)

    #if($group.isCommunity())

        $commList.add($group)
    #end
  #end

  #foreach($comm in $commList)
    ## Exclude Control Panel which is also validated as Community in LR
    #if($comm.getName()!="Control Panel")
        #if($comm.hasPublicLayouts())
            <a href="$comm.getFriendlyURL()">$comm.getName()</a><br />
         #elseif($comm.hasPrivateLayouts() && $is_signed_in)
            ## Community is private so only print this link if user authenticated
            <a href="$comm.getFriendlyURL()">$comm.getName()</a><br />
         #end
    #end
  #end

编辑 - 这是其他人发布的类似片段 https://stackoverflow.com/a/8457759/417933