使用 XStream 反序列化空 XML 元素

Question

在我收到的 XML 流中，我有以下语句

<user>
    <age/>
</user>

，该语句将插入到如下所示的对象中：

@XStreamAlias("user")
public class User {

    public int age = 0;
}

不幸的是，每次尝试读取此 XML 时，我都会收到 XStream 异常，因为age xml 标记为空：

Exception in thread "main" com.thoughtworks.xstream.converters.ConversionException: For input string: "" : For input string: ""
---- Debugging information ----
message             : For input string: ""
cause-exception     : java.lang.NumberFormatException
cause-message       : For input string: ""
class               : java.lang.Integer
required-type       : java.lang.Integer
converter-type      : com.thoughtworks.xstream.converters.SingleValueConverterWrapper
wrapped-converter   : com.thoughtworks.xstream.converters.basic.IntConverter
path                : /GoodreadsResponse/user/age
line number         : 17
class[1]            : fr.riduidel.exporter.goodreads.User
converter-type[1]   : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
class[2]            : fr.riduidel.exporter.goodreads.GoodreadsResponse
version             : null
-------------------------------
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convert(TreeUnmarshaller.java:79)
    at com.thoughtworks.xstream.core.AbstractReferenceUnmarshaller.convert(AbstractReferenceUnmarshaller.java:65)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:66)
    at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.unmarshallField(AbstractReflectionConverter.java:355)
    at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.doUnmarshal(AbstractReflectionConverter.java:306)
    at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.unmarshal(AbstractReflectionConverter.java:234)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convert(TreeUnmarshaller.java:72)
    at com.thoughtworks.xstream.core.AbstractReferenceUnmarshaller.convert(AbstractReferenceUnmarshaller.java:65)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:66)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:50)
    at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.doUnmarshal(AbstractReflectionConverter.java:322)
    at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.unmarshal(AbstractReflectionConverter.java:234)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convert(TreeUnmarshaller.java:72)
    at com.thoughtworks.xstream.core.AbstractReferenceUnmarshaller.convert(AbstractReferenceUnmarshaller.java:65)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:66)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:50)
    at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:134)
    at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32)
    at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1052)
    at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1036)
    at com.thoughtworks.xstream.XStream.fromXML(XStream.java:921)

如何我告诉 XStream 将此字段视为“可选”或“可能不包含任何内容”？

Answer 1

不幸的是，这并不那么容易。有两种方法可以做到这一点：

• 使用 xslt 编写转换并将其应用到流，然后再使用 XStream 读取它，以便 xml 与您的 Java Bean 匹配，或者
• 编写您自己的 JavaBeanConverter 并将其注册到 XStream。通过这种方式，您可以详细定义如何将 xml 映射到 Java Bean。您可以在此问题上找到有关如何向 XStream 注册 JavaBeanConverter 的提示。