Java 中的多播不起作用
我正在为我的班级开发一些对等 2 对等应用程序,有人告诉我要让服务器发现彼此,他们必须多播到他们的 UDP 端口 1110 并监听他们的 UDP 端口 1110。我编写了如下代码来执行此操作。为了进行测试,我运行了两台服务器,它们既发送又接收。但似乎没有什么作用。你认为我的问题出在哪里?
我将两台服务器放在两个不同的文件夹中。我为我的网卡分配了 IP 地址,如下所示 ifconfig eth0:3 192.168.0.11 netmask 255.255.255.0 up
我应该如何告诉每个服务器新的 IP 地址?
BroadcastListner
class BroadcastListner implements Callable<Object> {
int PORT = 1110;
String IP = "255.255.255.255";
MulticastSocket socket ;
DatagramPacket packet;
InetAddress IPAD;
byte data[] = null ; //////////////change size
int numOfNodes;
BroadcastListner(String IP, int numOfNodes) {
try {
this.numOfNodes = numOfNodes;
this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket(PORT);
packet = new DatagramPacket(data,data.length);
} catch (Exception e) {
e.printStackTrace();
}
}
BroadcastListner(int numOfNodes) {
try{
this.numOfNodes = numOfNodes;
// this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket(PORT);
packet = new DatagramPacket(data,data.length);
} catch (Exception e) {
e.printStackTrace();
}
}
public String call() {
try{
socket.joinGroup(IPAD);
} catch (Exception e) {
e.printStackTrace();
return "";
}
while(true) {
try {
socket.receive(packet);
String str = new String(packet.getData());
System.out.println(" Time signal received from"+
packet.getAddress() + " Time is : " +str);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
//socket.leaveGroup(IPAD);
//socket.close();
//return "";
}
}
BroadcastSender
class BroadcastSender implements Callable<Object> {
int PORT = 1110;
String IP = "255.255.255.255";
MulticastSocket socket;
DatagramPacket packet;
InetAddress IPAD;
byte[] data = "IAmAServer".getBytes();
//int numOfNodes;
String str = "IAmAServer";
BroadcastSender(String IP) {
try {
// this.numOfNodes = numOfNodes;
this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket();
} catch (Exception e) {
e.printStackTrace();
}
}
BroadcastSender() {
try{
// this.numOfNodes = numOfNodes;
// this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket();
} catch (Exception e) {
e.printStackTrace();
}
}
public String call() {
try {
socket.joinGroup(IPAD);
socket.setTimeToLive(10);
} catch (Exception e) {
e.printStackTrace();
return "";
}
while(true) {
try {
Thread.sleep(2000);
packet = new DatagramPacket (data,str.length(),IPAD,PORT);
socket.send(packet);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
//return "";
}
}
I'm developing some peer 2 peer app for my class and I was told for letting servers to discover each other they have to Multicast to their UDP port 1110 and listen to their UDP port 1110. I wrote the code like below for doing that. for testing I run 2 servers which both send and receive. but it seems nothing working. where do you think my problem is ?
I put 2 servers in 2 different folders. and I assigned to IP addresses to my NIC like this ifconfig eth0:3 192.168.0.11 netmask 255.255.255.0 up
how should I tell each server about the new ip address?
BroadcastListner
class BroadcastListner implements Callable<Object> {
int PORT = 1110;
String IP = "255.255.255.255";
MulticastSocket socket ;
DatagramPacket packet;
InetAddress IPAD;
byte data[] = null ; //////////////change size
int numOfNodes;
BroadcastListner(String IP, int numOfNodes) {
try {
this.numOfNodes = numOfNodes;
this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket(PORT);
packet = new DatagramPacket(data,data.length);
} catch (Exception e) {
e.printStackTrace();
}
}
BroadcastListner(int numOfNodes) {
try{
this.numOfNodes = numOfNodes;
// this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket(PORT);
packet = new DatagramPacket(data,data.length);
} catch (Exception e) {
e.printStackTrace();
}
}
public String call() {
try{
socket.joinGroup(IPAD);
} catch (Exception e) {
e.printStackTrace();
return "";
}
while(true) {
try {
socket.receive(packet);
String str = new String(packet.getData());
System.out.println(" Time signal received from"+
packet.getAddress() + " Time is : " +str);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
//socket.leaveGroup(IPAD);
//socket.close();
//return "";
}
}
BroadcastSender
class BroadcastSender implements Callable<Object> {
int PORT = 1110;
String IP = "255.255.255.255";
MulticastSocket socket;
DatagramPacket packet;
InetAddress IPAD;
byte[] data = "IAmAServer".getBytes();
//int numOfNodes;
String str = "IAmAServer";
BroadcastSender(String IP) {
try {
// this.numOfNodes = numOfNodes;
this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket();
} catch (Exception e) {
e.printStackTrace();
}
}
BroadcastSender() {
try{
// this.numOfNodes = numOfNodes;
// this.IP = IP;
IPAD = InetAddress.getByName(IP);
socket = new MulticastSocket();
} catch (Exception e) {
e.printStackTrace();
}
}
public String call() {
try {
socket.joinGroup(IPAD);
socket.setTimeToLive(10);
} catch (Exception e) {
e.printStackTrace();
return "";
}
while(true) {
try {
Thread.sleep(2000);
packet = new DatagramPacket (data,str.length(),IPAD,PORT);
socket.send(packet);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
//return "";
}
}
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您需要尝试 192.168.0.255 的广播地址。
另一种方法是使用多播而不是像 224.xxx 这样不与特定子网绑定的广播地址。
You need to try the broadcast address of 192.168.0.255
An alternative is to use a multi-cast instead of broadcast address like 224.x.x.x which is not tied to a specific subnet.