JXTable 中 JComboBox 的问题

Question

我正在尝试将 JXTable 中的一列设为组合框。很难解释我面临的问题。当您单击下拉菜单时，有时下拉菜单不会保持打开状态足够长的时间，以便您选择值。它只是关闭并选择一些值。有时它会保持开放状态供您选择一个值。 这是 SSCCE：

import java.awt.Color;

import javax.swing.ComboBoxModel;
import javax.swing.DefaultCellEditor;
import javax.swing.DefaultComboBoxModel;
import javax.swing.JComboBox;
import javax.swing.table.DefaultTableModel;

import org.jdesktop.swingx.JXFrame;
import org.jdesktop.swingx.JXTable;
import org.jdesktop.swingx.renderer.CellContext;
import org.jdesktop.swingx.renderer.ComponentProvider;
import org.jdesktop.swingx.renderer.DefaultTableRenderer;

public class Test {

    public static void main(String[] args) {
        JXFrame frame=new JXFrame();
        Object[][] rows = new Object[10][];

        for (int i = 0; i < rows.length; i++) {
        rows[i] = new Object[]{
        "Test data ","Yes"};
        }

        DefaultTableModel model = new DefaultTableModel(rows,
        new String[]{
        "Title 1", "Title 2"
        });

        final JXTable table = new JXTable(model);
        DefaultComboBoxModel cmodel = new DefaultComboBoxModel(new String[] {"Yes","No","Maybe"});
        table.getColumnExt(1).setCellRenderer(new DefaultTableRenderer(new ComboBoxProvider(cmodel)));
        table.getColumnExt(1).setCellEditor(new ComboBoxEditor(cmodel));
        table.setVisibleRowCount(10);
    frame.setContentPane(table);
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    frame.pack();
        frame.setVisible(true);
    }
}

class ComboBoxEditor extends DefaultCellEditor {
    public ComboBoxEditor(ComboBoxModel model) {
        super(new JComboBox(model));
    }
}

class ComboBoxProvider extends ComponentProvider<JComboBox> {
    private static final long serialVersionUID = 1L;
    private JComboBox box;
    public ComboBoxProvider(ComboBoxModel model){
        box.setModel(model);
    }
    @Override
    protected void configureState(CellContext context) {
        box.setForeground(Color.black);
    }
    @Override
    protected JComboBox createRendererComponent() {
        box = new JComboBox();
        box.setForeground(Color.black);
        return box;
    }
    @Override
    protected void format(CellContext context) {
        box.setForeground(Color.black);
        rendererComponent.setSelectedItem(context.getValue());
    }
}

Answer 1

要解决此问题，请确保您不为编辑器和渲染器共享相同的 DefaultComboxBoxModel 实例。因此，不要这样做：

DefaultComboBoxModel cmodel = new DefaultComboBoxModel(new String[] {"Yes","No","Maybe"});
    table.getColumnExt(1).setCellRenderer(new DefaultTableRenderer(new ComboBoxProvider(cmodel)));
    table.getColumnExt(1).setCellEditor(new ComboBoxEditor(cmodel));

这样做：

    table.getColumnExt(1).setCellRenderer(new DefaultTableRenderer(new ComboBoxProvider(
             new DefaultComboBoxModel(new String[] {"Yes","No","Maybe"}))));
    table.getColumnExt(1).setCellEditor(new ComboBoxEditor(
            new DefaultComboBoxModel(new String[] {"Yes","No","Maybe"})));