如何使用printf函数？
我有一个关于 C++ 中的 printf 函数的快速问题。
如何使用 printf 函数将此 for 循环放到屏幕上？
for (int count = 0; count < numberOfEmployees; count++) {
cout << employees[count].name << " \t" << employees[count].title << " \t" <<
gross << "\t" << tax << "\t" << net << "\n";
}
因此，我需要取出 cout 并调用 printf。
它必须看起来像这样，但没有点：
每周工资单：
姓名 .. 标题 ... 总... 税... Net
Ebenezer .... 合作伙伴 .... 250.00...... 62.25 。 ... 187.75
鲍勃·克拉奇特 职员 ...... 15.00 ...... 2.00 ...... 13.00
I have a quick question about the printf function in c++.
How do I put this for loop onto the screen with the printf function?
for (int count = 0; count < numberOfEmployees; count++) {
cout << employees[count].name << " \t" << employees[count].title << " \t" <<
gross << "\t" << tax << "\t" << net << "\n";
}
So, I need to take out the cout and put in a call to printf.
It has to look like this, but without the dots:
Weekly Payroll:
Name .. Title ... Gross... Tax... Net
Ebenezer .... Partner.... 250.00...... 62.25 .... 187.75
Bob Cratchit Clerk ...... 15.00 ......... 2.00 ...... 13.00
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评论（2）
你可以
假设 name 和 title 是 c 风格的字符串，gross、tax、net 是整数，很可能它们都不是这些类型……但给你一种感觉。 printf 文档提供了打印各种基本类型的指南。
you can do
assuming name and title are c style strings, and gross, tax,net are ints, most likely none of them are those types....but gives you the feel for it. the printf documentation gives a guide for printing out the various basic types.
printf 的想法是，您有一个“格式字符串”，其中包含要由提供的值填充的占位符。在您的情况下，格式字符串可能看起来像“%s \t%s \t%f\t%f\t%f\n”，其中每个占位符以 % 开头，后跟如何解释的规范提供的值（例如，s 表示字符串，f 表示浮点数）。还有更多的选项（例如字段大小、小数位数、左对齐或右对齐），但这就是基本思想。
The idea w/ printf is that you have a "format string" with placeholders to be filled in by supplied values. In your case, the format string might look like "%s \t%s \t%f\t%f\t%f\n", where each placeholder starts w/ a % followed by a specification of how to interpret the supplied value (for example, s means a string and f means a float). There are a lot more options than that (things like field sizes, # of decimal places, left-or-right alignment), but that's the basic idea.