Groovy类加载器行为
GroovyClassloader 行为理解，
ScriptEngineManager factory = new ScriptEngineManager();
ScriptEngine engine = factory.getEngineByName("groovy");
GroovyScriptEngineImpl groovyEngineImpl = (GroovyScriptEngineImpl) engine;
在循环中，
for (int i = 0; i < 10; i++) {
long startTime = System.currentTimeMillis();
classLoader = new GroovyClassLoader(groovyEngineImpl.getClassLoader().getParent());
fileName = fileName + i;
Class groovyClass = classLoader.parseClass(s,fileName);
long endTime = System.currentTimeMillis();
System.out.println("Total elapsed time in execution o " + (endTime-startTime));
startTime = System.currentTimeMillis();
groovyClass = classLoader.parseClass(s,fileName);
endTime = System.currentTimeMillis();
System.out.println("Second Time Total elapsed time in execution o " + (endTime-startTime));
}
我对上述代码有几个问题：
- 在 for 循环中，我正在创建一个新的 groovyclassloder 对象，并且 解析 groovy 脚本两次。当循环迭代时 第二次，并尝试再次解析 groovyscript，会发生什么 发生 ？
- 当另一个对象第二次创建时会发生什么。 类加载器是否会设法从类路径中获取类？ 再次重新编译一遍？
- 当重新编译被触发时，groovy如何知道源是什么 改变了？
GroovyClassloader behaviour understanding ,
ScriptEngineManager factory = new ScriptEngineManager();
ScriptEngine engine = factory.getEngineByName("groovy");
GroovyScriptEngineImpl groovyEngineImpl = (GroovyScriptEngineImpl) engine;
in a loop,
for (int i = 0; i < 10; i++) {
long startTime = System.currentTimeMillis();
classLoader = new GroovyClassLoader(groovyEngineImpl.getClassLoader().getParent());
fileName = fileName + i;
Class groovyClass = classLoader.parseClass(s,fileName);
long endTime = System.currentTimeMillis();
System.out.println("Total elapsed time in execution o " + (endTime-startTime));
startTime = System.currentTimeMillis();
groovyClass = classLoader.parseClass(s,fileName);
endTime = System.currentTimeMillis();
System.out.println("Second Time Total elapsed time in execution o " + (endTime-startTime));
}
I have a couple of questions regarding the above code:
- In a for loop I'm creating a new groovyclassloder object, and
parsing the groovy script twice. When the loop iterates for the
second time, and tries to parse the groovyscript again, what will
occur ? - What will happen on the second time when another object is created.
Will the classloader manage to get the class form the classpath or
again recompile it again? - When recompile is triggered, how does groovy know what the source is
changed?
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s的类型。如果它是一个文件，它将检查是否需要重新编译，如果不需要，它将使用相同的类。如果它是一个String或其他东西，那么它必须再次从该字符串重新编译类s. If it is a file, it will check if it needs a recompile, and if not it will use the same class. If it is aStringor something, then it will have to recompile the class from theis String again