使用 Javamail API 列出收件箱

发布于 2025-01-01 07:02:27 字数 1113 浏览 5 评论 0原文

我正在获取我的 gmail 帐户的收件箱文件夹,可以列出传入的电子邮件,但该列表是从较旧的邮件到较新的邮件列出的。我怎样才能恢复它?

    public class readInbox extends ListActivity{

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
//setContentView(R.layout.readmail);

Message[] messages = new Message[] { };

try {
    messages = inboxReader.getMail();
} 
catch (MessagingException e) {
    Log.e("mailReader getMail error. in readmail.java", e.getMessage(), e);
}



ArrayAdapter<Message> adapter = new ArrayAdapter<Message>(this,
R.layout.simple_list_item_1 ,messages){
    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        Message message = getItem(position);
        TextView resultView = new TextView(super.getContext());
        try {
            resultView.setText(message.getSubject());
        } 
        catch (MessagingException e) {
            Log.e("resultView.setText in readmail", e.getMessage(), e);
        }
        return resultView;
    }
};

setListAdapter(adapter);
}
}

I'm getting inbox folder of my gmail account, can list the incoming e-mails, but that list is being listed from older mails to newer mails. How can i revert that ?

    public class readInbox extends ListActivity{

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
//setContentView(R.layout.readmail);

Message[] messages = new Message[] { };

try {
    messages = inboxReader.getMail();
} 
catch (MessagingException e) {
    Log.e("mailReader getMail error. in readmail.java", e.getMessage(), e);
}



ArrayAdapter<Message> adapter = new ArrayAdapter<Message>(this,
R.layout.simple_list_item_1 ,messages){
    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        Message message = getItem(position);
        TextView resultView = new TextView(super.getContext());
        try {
            resultView.setText(message.getSubject());
        } 
        catch (MessagingException e) {
            Log.e("resultView.setText in readmail", e.getMessage(), e);
        }
        return resultView;
    }
};

setListAdapter(adapter);
}
}

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评论(2

雨后彩虹 2025-01-08 07:02:27

要么反转数组的顺序,要么对于 getItem ,使用恢复的索引 (count-position-1) 。

顺便说一句,这不是使用 listviews 的有效方法,事实上它有内存泄漏,这会导致它在处理大量项目后崩溃(对于 SGS3 来说大约 10000 就足够了)。

有关 listView 的更多信息,请观看此视频:

http ://www.google.com/events/io/2010/sessions/world-of-listview-android.html

either invert the order of the array , or for the getItem , use the reverted index (count-position-1) .

btw, that's not an efficient way to use listviews , and in fact it has a memory leak which will cause it to crash after a lot of items (about 10000 is enough for SGS3) .

for more information about listView , check this video:

http://www.google.com/events/io/2010/sessions/world-of-listview-android.html

琉璃繁缕 2025-01-08 07:02:27

您可以通过inbox.getMessageCount()获取消息总数,然后检索最后N条消息。

Message messages[] = inbox.getMessages(inbox.getMessageCount() - 25 , inbox.getMessageCount());

You can get the total number of messages through inbox.getMessageCount(), then retrieve last N number of messages.

Message messages[] = inbox.getMessages(inbox.getMessageCount() - 25 , inbox.getMessageCount());
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