如何在 C# 中忽略参数序列化

发布于 2025-01-01 05:05:00 字数 323 浏览 0 评论 0原文

我有一个需要在 C# 中序列化的对象，但是该对象具有以下属性：

[XmlElement("NodeConfiguration")]
public NodeConfigurationSerialize NodeConfiguration { get; set; }

在序列化期间必须忽略该属性，并且在反序列化期间必须考虑该属性，换句话说，我需要以这样的方式配置该属性：仅被序列化过程忽略。

有谁知道这是否可能？如果是这样，我该怎么办？

注意：我使用的是 Visual Studio 2010 和 .NET Framework 4.0。

原文

I have an object that I need to serialize in C#, however this object has the property:

[XmlElement("NodeConfiguration")]
public NodeConfigurationSerialize NodeConfiguration { get; set; }

This property must be ignored during the serialization and must be considered during the deserialization, in other words I need to configure this property in such a way that it is only ignored by the serialization process.

Does anyone know if this is possible? If so, how can I do it?

Note: I am using the Visual Studio 2010 and the .NET Framework 4.0.

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段念尘 2025-01-08 05:05:00

我认为您的设计需要进行一些小改动。您需要某种方式来表示“未设置”：

[XmlElement(IsNullable = true)]
public NodeConfigurationSerialize ? NodeConfiguration { get; set; }

当您不想设置它时，将其设置为“null”，当您这样做时，您可以将其设置为您想要的任何值。现在您可以自动使用序列化/反序列化，而无需手动编辑文件。

I think small change in your design is needed. You need some way to say 'this isn't set':

[XmlElement(IsNullable = true)]
public NodeConfigurationSerialize ? NodeConfiguration { get; set; }

When you don't want it set, set it to 'null', when you do, you can set it to whatever you want. Now you can automatically use serialization/deserialization without needing to manually edit the files.

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通知家属抬走 2025-01-08 05:05:00

您可以实现 System.Xml.Serialization.IXmlSerialized 接口：

public NodeConfigurationSerialize : IXmlSerializable
{
    public void ReadXml(System.Xml.XmlReader reader) 
    {
        this.value = (String)reader.ReadElementContentAs(typeof(String), null);
    }

    public void WriteXml(System.Xml.XmlWriter writer) 
    {
        // do nothing
    }
}

You could implement the System.Xml.Serialization.IXmlSerializable interface:

public NodeConfigurationSerialize : IXmlSerializable
{
    public void ReadXml(System.Xml.XmlReader reader) 
    {
        this.value = (String)reader.ReadElementContentAs(typeof(String), null);
    }

    public void WriteXml(System.Xml.XmlWriter writer) 
    {
        // do nothing
    }
}

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