给定地址总线宽度和各种信息的可用字节数
一个处理器有
- 24位地址总线
- 16位数据总线
- 字包含2个字节
- 可寻址
外围设备和内存单元将被连接，并且很可能会使用整个内存空间。
有很多问题，我只使用过 24 位地址总线这一事实。
系统的可寻址位置总数是多少？ 2^24
1/4的地址空间用于外设，外设的地址总数是多少？ 2^24/2^2
12/16 个地址将用于磁盘寻址，有多少个？ (12/16)2^22
3/4的地址空间用于RAM和ROM的内存需求，可用的地址总数是多少？ (3/4)2^24
这似乎很容易
A processor has
- 24 bit address bus
- 16 bit data bus
- word contains 2 bytes
- byte addressable
Peripherals and memory units will be connected and the entire memory space most likely will be used.
There are quite a few questions and I only ever use the fact that there is a 24 bit address bus.
What is the total number of addressable locations for the system? 2^24
1/4 of the address space is to be used for the peripherals, what is the total number of addresses for peripherals? 2^24/2^2
12/16 of the addresses are to be used for disk addressing, how many? (12/16)2^22
3/4 of the address space are to be used for memorey requirements of RAM and ROM, what is the total number of addresses avaliable? (3/4)2^24
This seems to easy
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除了一个答案（可能是拼写错误）之外，您的数学是正确的。
2^24 = 16,777,2162^24/2^2(?) = (1/4)2^24 = 4,194,304(12/16)2^22(12/16)2^24 = (3/4)2^24 = 12,582,912(3/4)2^24 = 12,582,912（与 3 相同。）Except for one answer (which might be a typo), your math is correct.
2^24 = 16,777,2162^24/2^2(?) = (1/4)2^24 = 4,194,304(12/16)2^22(12/16)2^24 = (3/4)2^24 = 12,582,912(3/4)2^24 = 12,582,912(same as 3.)