文件解析期间访问冲突写入位置

发布于 2025-01-01 00:56:47 字数 590 浏览 2 评论 0原文

我已经将问题缩小到几行代码，但我无法识别导致“访问冲突写入位置”的函数调用的非法内容，我希望更好的 C 语言可以帮助我？

代码中断的输入是

vn 0.185492 -0.005249 0.982604

我想将 3 个浮点值分配给 Struct vn 数组

struct Normals{
    float vn1;
    float vn2;
    float vn3;
};
struct Normals vn[50000];

，而崩溃的代码是

if (line[0] == 'v' && line[1] == 'n' && line[1] != 't'){
    sscanf(line, "%*c%*c%f%f%f", 
            &vn[normCount].vn1, 
            &vn[normCount].vn2, 
            vn[normCount].vn3);
    normCount++;
    }

任何提示都很棒！谢谢

原文

Ive narrowed the issue down to a few lines of code but im having trouble identifying what is illegal about the function call causing a "Access violation writing location" I was hoping someone better with C could help me out?

The input the code is breaking on is

vn 0.185492 -0.005249 0.982604

I want to assign the 3 float values to an Array of Struct vn

struct Normals{
    float vn1;
    float vn2;
    float vn3;
};
struct Normals vn[50000];

and the code that is crashing is

if (line[0] == 'v' && line[1] == 'n' && line[1] != 't'){
    sscanf(line, "%*c%*c%f%f%f", 
            &vn[normCount].vn1, 
            &vn[normCount].vn2, 
            vn[normCount].vn3);
    normCount++;
    }

Any tips would be great! Thanks

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夜雨飘雪 2025-01-08 00:56:47

您忘记了 vn[normCount].vn3 之前的 &。

顺便说一句， line[1] == 'n' && 的意义是什么？行[1] != 't'?

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内心激荡 2025-01-08 00:56:47

提供给 scanf 的参数类型我错误：

    sscanf(line, "%*c%*c%f%f%f",            
        &vn[normCount].vn1, 
        &vn[normCount].vn2, 
        &vn[normCount].vn3); // address

the type of arguments supplied to scanf i wrong:

    sscanf(line, "%*c%*c%f%f%f",            
        &vn[normCount].vn1, 
        &vn[normCount].vn2, 
        &vn[normCount].vn3); // address

回复收藏 0 原文

揪着可爱 2025-01-08 00:56:47

sscanf(line, "%*c%*c%f%f%f", &vn[normCount].vn1, &vn[normCount].vn2, vn[normCount].vn3);
                                                                    ^^^^

您忘记了 &。这导致 vn[normCount].vn3 中包含的值被评估为内存地址（您显然无权写入）。

sscanf(line, "%*c%*c%f%f%f", &vn[normCount].vn1, &vn[normCount].vn2, vn[normCount].vn3);
                                                                    ^^^^

You forgot an &. This is causing the value contained in vn[normCount].vn3 to be evaluated as a memory address (which you obviously don't have access to write to).

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