将值数组放入 CLLocationCooperative2D 的优雅方法
是否有一种优雅的方法从 NSDecimalNumber 值数组创建 CLLocationCooperative2D 对象？也许是一个递归函数？
我是目标 C 的新手，对此遇到困难。
下面是我正在使用的数据结构的示例。
NSDecimalNumber 值的数组：
NSLog(@"path: %@", [path description]);
返回
path: (
"-71.4826609644423",
"27.7231737704478",
"-71.4826608497223",
"27.7231120144099",
"-71.4826391681679",
"27.7228678610506",
...
"-71.482414263977",
"27.7225217655116",
)
我可以像这样手动创建 CLLocationCooperative2D 对象：
CLLocationCoordinate2D pathCoords[5]={
CLLocationCoordinate2DMake(27.7231737704478,-71.4826609644423),
CLLocationCoordinate2DMake(27.7231120144099,-71.4826608497223),
CLLocationCoordinate2DMake(27.7228678610506,-71.4826391681679),
...
CLLocationCoordinate2DMake(27.7225217655116,-71.482414263977),
};
欢迎任何编码建议。 谢谢！
Is there an elegant way to create a CLLocationCoordinate2D object from an array of NSDecimalNumber values? Perhaps a recursive function?
I'm new to objective C and am having difficulty with this.
Below is an example of the data structures I'm working with.
an array of NSDecimalNumber values:
NSLog(@"path: %@", [path description]);
returns
path: (
"-71.4826609644423",
"27.7231737704478",
"-71.4826608497223",
"27.7231120144099",
"-71.4826391681679",
"27.7228678610506",
...
"-71.482414263977",
"27.7225217655116",
)
I can manually create the CLLocationCoordinate2D object like this:
CLLocationCoordinate2D pathCoords[5]={
CLLocationCoordinate2DMake(27.7231737704478,-71.4826609644423),
CLLocationCoordinate2DMake(27.7231120144099,-71.4826608497223),
CLLocationCoordinate2DMake(27.7228678610506,-71.4826391681679),
...
CLLocationCoordinate2DMake(27.7225217655116,-71.482414263977),
};
Any coding suggestions are welcome.
Thanks!
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评论（2）
我假设您已经创建了一个名为
pathCoords的CLLocationCooperative2D结构，大小为 5。您的问题的本质不是递归的，因此如果您采用递归，那就太过分了。
I'm assuming you have already created a
CLLocationCoordinate2Dstructure calledpathCoordsof size 5.The nature of your problem is not recursive, so if you go recursive - it's an overkill.
最终的解决方案包括将 NSDecimalNumbers 类型转换为 doubleValues：
The final solution including typecasting the NSDecimalNumbers to doubleValues: