使用 Zend Gdata 创建 Google 地图

Question

我已经弄清楚如何使用 Zend Gdata 对地址进行地理编码，但我什至不知道如何检索返回的 JSON 片段。这是地理编码器：

include_once('Zend/Gdata.php');
$client = new Zend_Http_Client('http://maps.googleapis.com/maps/api/geocode/json');

$urlencodedAddress = urlencode('1600 Pennsylvania Avenue, N.W. Washington, DC 20500');

$client->setParameterGet('sensor', 'false');
$client->setParameterGet('address', $urlencodedAddress); 
$response = $client->request('GET');    

这是响应对象：

Zend_Http_Response Object ( [version:protected] => 1.1 [code:protected] => 200 [message:protected] => OK [headers:protected] => Array ( [Content-type] => application/json; charset=UTF-8 [Date] => Mon, 30 Jan 2012 03:26:25 GMT [Expires] => Tue, 31 Jan 2012 03:26:25 GMT [Cache-control] => public, max-age=86400 [Vary] => Accept-Language [Server] => mafe [X-xss-protection] => 1; mode=block [X-frame-options] => SAMEORIGIN [Connection] => close ) [body:protected] => { "results" : [ { "address_components" : [ { "long_name" : "1600", "short_name" : "1600", "types" : [ "street_number" ] }, { "long_name" : "Pennsylvania Ave NW", "short_name" : "Pennsylvania Ave NW", "types" : [ "route" ] }, { "long_name" : "Northwest Washington", "short_name" : "Northwest Washington", "types" : [ "neighborhood", "political" ] }, { "long_name" : "Washington", "short_name" : "Washington", "types" : [ "locality", "political" ] }, { "long_name" : "District of Columbia", "short_name" : "DC", "types" : [ "administrative_area_level_1", "political" ] }, { "long_name" : "United States", "short_name" : "US", "types" : [ "country", "political" ] }, { "long_name" : "20500", "short_name" : "20500", "types" : [ "postal_code" ] } ], "formatted_address" : "1600 Pennsylvania Ave NW, Washington, DC 20500, USA", "geometry" : { "location" : { "lat" : 38.89871490, "lng" : -77.03765550 }, "location_type" : "ROOFTOP", "viewport" : { "northeast" : { "lat" : 38.90006388029150, "lng" : -77.03630651970849 }, "southwest" : { "lat" : 38.89736591970851, "lng" : -77.03900448029150 } } }, "partial_match" : true, "types" : [ "street_address" ] } ], "status" : "OK" } )

我真的想使用数据来创建一张分割地图，一个带有标记的普通地图和一个显示街景的分割视图。有什么建议吗？

Answer 1

你可以这样做

// get json object 
json_decode($response->getBody());

参考文献。 http://framework.zend.com/manual/en/zend.http .response.html

Answer 2

确实，答案是忘记 Zend。真是浪费时间。做起来简单多了：

$urlencodedAddress = urlencode('1600 Pennsylvania Avenue, N.W. Washington, DC 20500');

$details_url = "http://maps.googleapis.com/maps/api/geocode/json?address=" . $urlencodedAddress . "&sensor=false";

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $details_url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$geoloc = json_decode(curl_exec($ch), true);


var_dump($geoloc['results'][0]['geometry']['location']['lat']);
var_dump($geoloc['results'][0]['geometry']['location']['lng']);

cUrl 是我最好的朋友。