将变量传递给 JavaScript 函数
您好，有人可以告诉我为什么此代码不正确吗？我正在尝试将两个变量值传递给函数。
$( "#resizable-text1, #resizable-text2" ).draggable({
containment: "#containment-wrapper1",
scroll: false,
stop: function(event, ui)
{
var id = $(this).attr('data-idSuffix');
adjust_pos($('#resizable-text',id));
}
});
function adjust_pos(elem, id) {
alert('elem = '+elem)
alert('id = '+id)
var currentPos = $("#"+elem+id).position()
var xpos = parseInt(currentPos.left)
var ypos = parseInt(currentPos.top)
then use variables ele and id...
}
任何帮助表示赞赏。
Hi can someone please tell me why this code is incorrect? I'm trying to pass two variable values to a function.
$( "#resizable-text1, #resizable-text2" ).draggable({
containment: "#containment-wrapper1",
scroll: false,
stop: function(event, ui)
{
var id = $(this).attr('data-idSuffix');
adjust_pos($('#resizable-text',id));
}
});
function adjust_pos(elem, id) {
alert('elem = '+elem)
alert('id = '+id)
var currentPos = $("#"+elem+id).position()
var xpos = parseInt(currentPos.left)
var ypos = parseInt(currentPos.top)
then use variables ele and id...
}
Any help appreciated.
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评论（4）
您不需要将字符串包装在 jQuery
$()函数中，因为在您的函数中您无论如何都会这样做 ($("#"+elem+id).position( ））。只需发送字符串即可。所以这应该有效：
编辑： 另外，无论是在您的函数
adjust_pos中还是在您传递的参数中，您都应该删除#因为否则会出现是两个。我建议您在函数中删除，因此如果由于某种原因您想发送类选择器，您也可以这样做。You don't need to wrap the string in the jQuery
$()function, because in your function you will do that anyways ($("#"+elem+id).position()). Simply send the string.So this should work:
EDIT: Also, either in your function
adjust_posor in the parameter you pass you should remove a#because otherwise there would be two. I recommend you remove in the function, so if for some reason you want to send a class selector, you can do that too.根据您的
adjustment_pos 函数代码，它就像是adjustment_pos('resizing-text', id);According your code of
adjust_posfunction, it is like to beadjust_pos('resizable-text', id);看起来你的第二个右括号位于错误的位置：
Update
正如注释中所指出的，考虑到函数对参数所做的操作，您实际上不需要传入 jQuery 对象。您只需将元素的 id 作为字符串传递即可。
给定您当前的代码，您可以执行以下操作：
或者对 japrescott 建议的代码进行调整（从函数中删除哈希并将其作为参数的一部分传递）：
Looks like your second closing bracket is in the wrong place:
Update
As has been pointed out in the comments, you don't actually need to pass in the jQuery object given what your function does with the parameter. You simply need to pass in the id of the element as a string.
Given your current code you can do:
or with the adjustment to your code that japrescott recomended (removing the hash from the function and passing it in as part of the parameter):
这条线；
一定是这样的；
this line;
must be like this;