从日期字符串中检索年份和月份

Question

我想从这种日期中检索年份和月份：2011-12-23 10:45:01 但没有运气。

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setTimeZone:[NSTimeZone timeZoneWithName:@"GMT"]];
[dateFormatter setDateFormat:@"yyyy"];
NSLog(@"Date = %@",[dateFormatter dateFromString:@"2011-12-23 10:45:01"]);
[dateFormatter release];

Date = (null)，我不明白为什么。

Answer 1

你必须分两步完成，首先匹配整个日期，然后输出你想要的位：

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setTimeZone:[NSTimeZone timeZoneWithName:@"GMT"]];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
NSDate *date = [dateFormatter dateFromString:@"2011-12-23 10:45:01"];

//now you have the date, you can output the bits you want

[dateFormatter setDateFormat:@"yyyy"];
NSString *year = [dateFormatter stringFromDate:date];

[dateFormatter setDateFormat:@"MM"];
NSString *month = [dateFormatter stringFromDate:date];

[dateFormatter release];

Answer 2

这已经在 将 NSDate 格式化为特定样式中得到了回答对于年、月、日和时、分、秒。

具体来说：

NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd"];

NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setDateFormat:@"HH:mm:ss"];

NSDate *now = [[NSDate alloc] init];

NSString *theDate = [dateFormat stringFromDate:now];
NSString *theTime = [timeFormat stringFromDate:now];

NSLog(@"\n"
  "theDate: |%@| \n"
  "theTime: |%@| \n"
  , theDate, theTime);

[dateFormat release];
[timeFormat release];
[now release];