长按手势时在 UIButton 中显示图像

Question

我有以下问题。我有一个 UIScrollView ，上面有几个按钮，这些按钮上的图标设置为图像。我的每个按钮都附有一个长按识别器。如何在长按手势时在发件人按钮上显示较小的删除图标？我的目标是创建当用户想要删除特定应用程序时 iOS 呈现的行为。 这是按钮的代码（带有图像）：

//set the button with the image of conference here.
UIButton * button = [UIButton buttonWithType:UIButtonTypeCustom];
button.frame = CGRectMake(3, 3, w-5, h-5);
CALayer * l = [button layer];
[l setMasksToBounds:YES];
[l setCornerRadius:8.0];
[button setImage:thumb forState:UIControlStateNormal];

button.property = confInfo;
[button addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside];
button.tag = i; 
bView.tag = i;

//Add gesture recognizer to be used for deletion of conference.
UILongPressGestureRecognizer *pahGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognizerStateChanged:)];

pahGestureRecognizer.minimumPressDuration = 1.0;
[button addGestureRecognizer:pahGestureRecognizer];

此代码位于循环中（请参阅代码中的 i）。我的长按操作是这样的：

- (void)longPressGestureRecognizerStateChanged:(UIGestureRecognizer *)gestureRecognizer {

      switch (gestureRecognizer.state) {

          case UIGestureRecognizerStateEnded:
               NSLog(@"Tapped!!!");                    
               break;

          default:
               break;
      }
 }

如何将我单击的按钮传递给此操作以在按钮的右上角显示较小的 X 图像？

Answer 1

您的手势识别器应通过 UIButton 的 view 属性附加到它。

case UIGestureRecognizerStateEnded:
    NSLog(@"Tapped!!!");
    [((UIButton*)gestureRecognizer.view) setImage:thumbWithX forState:UIControlStateNormal];
    break;