如何使用 PHP 解析包含特定字符串的文件中的一行？

发布于 2024-12-28 18:00:56 字数 850 浏览 1 评论 0原文

使用 PHP，我想从 RIPE IP 地址范围的 whois 记录中获取以 descr: 开头的行内容，因此它们应该看起来像这样：

% This is RIPE NCC's Routing Information Service
% whois gateway to collected BGP Routing Tables
% IPv4 or IPv6 address to origin prefix match
%
% For more information visit http://www.ripe.net/ris/riswhois.html

route:        53.0.0.0/8
origin:       AS31399
descr:        DAIMLER-AS Daimler Autonomous System
lastupd-frst: 2011-12-08 23:18Z  195.66.224.97@rrc01
lastupd-last: 2012-01-25 15:18Z  203.119.76.3@rrc00
seen-at:      rrc00,rrc01,rrc03,rrc04,rrc05,rrc07,rrc10,rrc11,rrc12,rrc13,rrc14,rrc15,rrc16
num-rispeers: 98
source:       RISWHOIS

所以我应该得到 DAIMLER -AS 戴姆勒自治系统 结果。

如何用最少的代码做到这一点，我在 $whois 中有记录。

<?php 
$whois = shell_exec('whois -h riswhois.ripe.net ' . $ip);
?>

原文

With PHP I want to get the content of the line starting with descr: out of a whois record from RIPE IP adress ranges, so they should all look something like this:

% This is RIPE NCC's Routing Information Service
% whois gateway to collected BGP Routing Tables
% IPv4 or IPv6 address to origin prefix match
%
% For more information visit http://www.ripe.net/ris/riswhois.html

route:        53.0.0.0/8
origin:       AS31399
descr:        DAIMLER-AS Daimler Autonomous System
lastupd-frst: 2011-12-08 23:18Z  195.66.224.97@rrc01
lastupd-last: 2012-01-25 15:18Z  203.119.76.3@rrc00
seen-at:      rrc00,rrc01,rrc03,rrc04,rrc05,rrc07,rrc10,rrc11,rrc12,rrc13,rrc14,rrc15,rrc16
num-rispeers: 98
source:       RISWHOIS

So I should get DAIMLER-AS Daimler Autonomous System as a result.

How to do this with a minimum of code, I have the record in $whois.

<?php 
$whois = shell_exec('whois -h riswhois.ripe.net ' . $ip);
?>

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旧故 2025-01-04 18:00:56

您可以使用 preg_match() 来完成此操作：

$whois = shell_exec('whois -h riswhois.ripe.net ' . $ip);
$result = preg_match('/^descr:\s*(.+)$/m', $matches);
$descr = $matches[1];

请注意 mutliline (m) 修饰符。

You can accomplish this using preg_match():

$whois = shell_exec('whois -h riswhois.ripe.net ' . $ip);
$result = preg_match('/^descr:\s*(.+)$/m', $matches);
$descr = $matches[1];

Note the use of the mutliline (m) modifier.

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很酷不放纵 2025-01-04 18:00:56

我首先将字符串拆分为行数组：

$lines = explode("\n", $whois);

然后循环遍历它们并找到以 descr:: 开头的字符串：

foreach($lines as $l) {
    if (strpos($l, 'descr:') === 0) { //We have a winner
        $description = trim(substr($l, strlen('descr:')));
    }
}

或者，您知道，使用像 Tim 那样的正则表达式解决方案。

I would start by splitting the string into an array of lines:

$lines = explode("\n", $whois);

Then loop through them and find the one that starts with descr::

foreach($lines as $l) {
    if (strpos($l, 'descr:') === 0) { //We have a winner
        $description = trim(substr($l, strlen('descr:')));
    }
}

Or, you know, use a Regex solution like Tim's.

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酒解孤独 2025-01-04 18:00:56

像 Tim 这样的 preg_match 解决方案将是最佳的，但只是提出第三个建议以供参考，特别是对于较短的字符串。同样的事情可以通过以下方式完成：

$descr_starts_at = strpos($my_text,"descr:") + 14;
$length = strpos($my_text,"lastupd-frst:") - 1 - $descr_starts_at;

$descr = substr($my_text, $descr_starts_at ,$length);

A preg_match solution like Tim's would be optimal but just to put a third suggestion out there for reference and especially for shorter strings. Same thing could be accomplished with:

$descr_starts_at = strpos($my_text,"descr:") + 14;
$length = strpos($my_text,"lastupd-frst:") - 1 - $descr_starts_at;

$descr = substr($my_text, $descr_starts_at ,$length);

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