c：带有函数实现的内联枚举
我遇到过一些 C 代码，其中有一个枚举类型，后跟一个函数实现，例如：
enum OGHRet funcX ( OGH *info, void *data, int size )
{
/* c code that does stuff here */
}
我对这个枚举语句如何与函数实现内联工作感到困惑。 我假设它是 funcX 的返回类型，但为什么用 enum 显式声明？
提前致谢。
I have come across some c code where the there is an enum type followed by a function implementation, such as this:
enum OGHRet funcX ( OGH *info, void *data, int size )
{
/* c code that does stuff here */
}
I am confused over how this enum statement works inline with the function implementation.
I assume it is the return type of funcX, but why is declared explicitly with enum?
Thanks in advance.
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它只是说它返回一个名为 OGHRet 的枚举，该枚举将在其他地方定义。
这是一段代码，显示了枚举和并排返回枚举的函数......
its just saying its returning an enum called OGHRet which will be defined elsewhere.
Here's a fragment of code that shows enums and functions that return enums side by side...
如果您像这样定义枚举类型：
那么
enum OGHRet只是类型的名称。您不能像OGHRet那样引用该类型；这是一个标签，仅在enum关键字之后可见。为该类型提供单字名称的唯一方法是使用 typedef ——但实际上没有必要这样做。如果您坚持能够调用类型
OGHRet而不是enum OGHRet，您可以这样做：这里声明枚举类型时不带标签，然后 typedef 创建它的别名。
If you define an enum type like this:
then
enum OGHRetis simply the name of the type. You can't refer to the type just asOGHRet; that's a tag, which is visible only after theenumkeyword.The only way to have a one-word name for the type is to use a typedef -- but it's really not necessary to do so. If you insist on being able to call the type
OGHRetrather thanenum OGHRet, you can do this:Here the enumeration type is declared without a tag, and then the typedef creates an alias for it.
也许是因为它没有声明为 typedef，如下所示：
这里您需要通过
enum OGHRet来引用它。要仅使用
OGHRet，您需要这样做：Maybe because it isn't declared as a typedef, like this:
Here you will need to make reference to this by
enum OGHRet.To use only
OGHRet, you need to do it like this:您需要
enum关键字来为OGHRet提供类型定义。在 C++ 中，可以省略它。另请参阅此问题。
You need the
enumkeyword to provide a type definition forOGHRet. In C++, you can omit it.See this question, as well.