NSRegularExpression 转义括号
我正在使用正则表达式来查找字符串中的一些值，但是，我试图找到的内容看起来像这样：
Dealt to SanderDecler [2s 5d]
但我似乎找不到一种方法来转义这些方括号，我也有同样的情况之前的括号问题。我试图像这样 \( 或 \[ 一样转义它们，但这没有给出任何匹配。所以我只是用点替换它，它确实匹配，但是，这似乎不是最好的方法这样做，我可以想象指定确切的字符对性能也更好...
所以我的问题是，如何匹配括号和方括号？
这是我的代码现在的样子，这是有效的，但不是最佳的：
NSString *expression =
@"^Dealt to (.{1,12}) .([0-9TJKQA][cdhs]) ([0-9TJKQA][cdhs]).";
NSRegularExpression *regex =
[NSRegularExpression regularExpressionWithPattern:expression
options:NSRegularExpressionAnchorsMatchLines
error:nil];
for (NSTextCheckingResult *result in [regex matchesInString:history options:NSMatchingReportCompletion range:NSMakeRange(0, history.length)])
{
NSLog(@"%@", [history substringWithRange:[result rangeAtIndex:0]]);
}
I'm using regular expressions to find some values in a string, however, what I'm trying to find looks something like this:
Dealt to SanderDecler [2s 5d]
But I can't seem to find a way to escape these square brackets, I've had the same problem with parentheses earlier. I've tried to escape them like this \( or \[, but that didn't give any matches. So I just replaced that with a dot, and it did match, however, that doesn't seem like the best way to do it, and I can imagine it's better for performance to specify the exact character too...
So my question is, how can I match parantheses and square brackets?
Here's how my code looks like now, this is working, but non-optimal:
NSString *expression =
@"^Dealt to (.{1,12}) .([0-9TJKQA][cdhs]) ([0-9TJKQA][cdhs]).";
NSRegularExpression *regex =
[NSRegularExpression regularExpressionWithPattern:expression
options:NSRegularExpressionAnchorsMatchLines
error:nil];
for (NSTextCheckingResult *result in [regex matchesInString:history options:NSMatchingReportCompletion range:NSMakeRange(0, history.length)])
{
NSLog(@"%@", [history substringWithRange:[result rangeAtIndex:0]]);
}
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试试这个：
Try this: