如何通过通配子目录自动生成make目标列表？
我想使用一个 Makefile 在数百个子目录中生成目标。每个子目录都是一个日期/时间戳，如下所示：20120119_153957，它与以下模式?????????_?????? 匹配。没有其他子目录与此模式匹配。
我想生成的一个目标名为 ??????_??????/graph.pdf。我有一个名为 make_graph 的脚本，它将根据给定的子目录名称生成图表。但我不确定如何编写一个 Makefile 来自动全局所有子目录并以编程方式生成这些目标。
例如，代码 SUBDIRS:=?????????_?????? 似乎正确地全局显示了所有子目录。我可以检查这个规则：
.PHONY: print
print:
echo $(SUBDIRS)
但是这个变量分配
TARGETS:=$(SUBDIRS:%=%/graph.pdf)
似乎没有达到我的预期并分配了很多很多的目标。相反，以下规则仅打印一个目标。
.PHONY: print
print:
echo $(TARGETS)
令人困惑的是，SUBDIRS 应该具有正确的子目录，但 TARGET 只有一个文件。
I would like to use a single Makefile to generate targets in hundreds of subdirectories. Each subdirectory is a date/time stamp like this: 20120119_153957, which matches the following pattern ????????_??????. There are no other subdirectories that match this pattern.
One target I would like to generate is called ????????_??????/graph.pdf. I have a script called make_graph that will make the graph given the subdirectory name. But I'm not sure how to write a Makefile that will automatically glob all of the subdirectores and generate these targets programmatically.
For example, the code SUBDIRS:=????????_?????? seems to correctly glob all of the subdirectories. I can check with this rule:
.PHONY: print
print:
echo $(SUBDIRS)
However this variable assignment
TARGETS:=$(SUBDIRS:%=%/graph.pdf)
does not seem to do what I expect and assign lots and lots of targets. Instead the following rule just prints one target.
.PHONY: print
print:
echo $(TARGETS)
It is very confusing that SUBDIRS should have the correct subdirectories but TARGET only has one file.
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在您的示例中，全局匹配由 shell 执行。
GNU Make 具有内置的
通配符函数 ，您可以按如下方式使用它：现在您可以使用此变量来构造目标列表：
另请参阅： 模式规则, 自动变量。
In your example glob matching is performed by the shell.
GNU Make has the built-in
wildcardfunction, which you can use as follows:Now you can use this variable to construct a list of targets:
See also: pattern rules, automatic variables.