@(posege Clk); 之间的区别a<=1'b1;和 @(posege Clk) a<= 1'b1;

发布于 2024-12-27 18:23:31 字数 239 浏览 2 评论 0 原文

有什么区别

@(posedge Clk);
   a<= 1'b1;

和

@(posedge Clk)
   a<= 1'b1;

注意Clk后面的分号。当我浏览测试平台时，我遇到了类似的代码行。我做了一些简单的实验，在模拟过程中我找不到任何差异。由于分号的存在/不存在，这些行后面的代码的执行顺序是否会发生任何变化？

原文

Is there any difference between

@(posedge Clk);
   a<= 1'b1;

and

@(posedge Clk)
   a<= 1'b1;

Note the semicolon after Clk. I came across similar lines of code when I was browsing through a testbench. I did some simple experiments and I could not find any differences during simulation. Will the sequence of execution for the code following these lines change in any way due to the presence/absence of the semicolon?

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冰魂雪魄 2025-01-03 18:23:31

任何过程语句的 BNF 语法本质上都是

statement_item := 
        {procedural_timing_control} statement;

这意味着您可以在任何语句前面有 0 个或多个时序控制。在您的示例中，@(thoughtge Clk) 是时序控制，a<= 1'b1; 是语句。

如果您的示例位于 fork/join 内，则会出现行为差异，因为前者是两个语句；后者是一种说法。

fork
  @(posedge Clk); a<=1'b1;
join

在这种情况下，这 2 个语句并行启动 - a 不会等待 posege 被分配。

The BNF syntax for any procedural statement is essentially

statement_item := 
        {procedural_timing_control} statement;

This means you can have 0 or more timing controls in front of any statement. In your example @(posedge Clk) is a timing control and a<= 1'b1; is the statement.

If your example were inside a fork/join, there would be a behavioral difference because the former is two statements; the later is one statement.