如何在android中从北获取任何地理位置的角度？

Question

在我的应用程序中，我想计算特定位置（给出纬度和经度）与北面的角度。有没有办法计算这个。实际上我已经找到了手机的方向，但我想获取位置角度来自北方。这是我的代码。请提出任何相关的解决方案。谢谢

   myAzimuth=Math.round(event.values[0]);
            myPitch=Math.round(event.values[1]);
            myRoll=Math.round(event.values[2]);
         Toast.makeText(this, "Value"+myAzimuth, Toast.LENGTH_SHORT).show();        
        if(myAzimuth<22){
        Toast.makeText(this, "North Direction", Toast.LENGTH_SHORT).show();     
        }

          else if (myAzimuth >= 22 && myAzimuth < 67)
              Toast.makeText(this, "North East", Toast.LENGTH_SHORT).show();        
          else if (myAzimuth >= 67 && myAzimuth < 112)
              Toast.makeText(this, "East Direction", Toast.LENGTH_SHORT).show();        
          else if (myAzimuth >= 112 && myAzimuth < 157)
              Toast.makeText(this, "South east Direction", Toast.LENGTH_SHORT).show();      
          else if (myAzimuth >= 157 && myAzimuth < 202)
              Toast.makeText(this, "South Direction", Toast.LENGTH_SHORT).show();       
          else if (myAzimuth >= 202 && myAzimuth < 247)
              Toast.makeText(this, "South west Direction", Toast.LENGTH_SHORT).show();      
          else if (myAzimuth >= 247 && myAzimuth < 292)
              Toast.makeText(this, "west Direction", Toast.LENGTH_SHORT).show();        
          else if (myAzimuth >= 292 && myAzimuth < 337)
              Toast.makeText(this, "North west Direction", Toast.LENGTH_SHORT).show();      
          else if (myAzimuth >= 337)
              Toast.makeText(this, "North Direction", Toast.LENGTH_SHORT).show();       

Answer 1

根据“从北边的位置角度”的含义，有几种可能的解决方案。其中之一是：

final float[] results= new float[3];
// The computed distance in meters is stored in results[0].
// If results has length 2 or greater, the initial bearing is stored in results[1].
// If results has length 3 or greater, the final bearing is stored in results[2].
Location.distanceBetween(refLat, refLong, 90.0f, 0.0f, results);
final float bearing = results[1];

您获得从参考位置到北极的航线方位。当遵循最短距离航向时，方位/航向会发生变化。

或者按照 Konstantin Pribluda 的建议更好（见下面的评论）

final float bearing = 0.0f;