iOS 5 检测重复/连续摇动

发布于 2024-12-27 11:25:04 字数 727 浏览 5 评论 0原文

我正在编写一个应用程序，它不仅需要检测用户的摇晃一次，而且需要连续检测。这个想法是，声音会在一次摇动时播放一次，如果设备连续摇动，声音会循环播放。

我已经使用 Shake API 和 Accelerometer API 对其进行了测试，但两者都没有达到我想要的效果。这是我到目前为止所得到的：

- (void)playAudioFile
{
    soundFile = [NSURL fileURLWithPath: [[NSBundle mainBundle] pathForResource:@"boing" ofType:@"wav"]];
    audioPlayer = [[AVAudioPlayer alloc] initWithContentsOfURL:soundFile error:nil];
    [audioPlayer setDelegate:self];
    [audioPlayer play];
}

- (void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration
{
    if (acceleration.x > 0.5 || acceleration.y > 0.5 || acceleration.z > 0.5) {
        [self playAudioFile];
        NSLog(@"Trigger @ 0.5x");
    }
}

原文

I am writing an app that will need to detect a users shake not only once but continuously. The idea is that a sound would play once on a single shake and the sound would loop if the device is continuously shaken.

I have tested it with the both the Shake API and Accelerometer API but neither do exactly what I want. Here is what I've got so far:

- (void)playAudioFile
{
    soundFile = [NSURL fileURLWithPath: [[NSBundle mainBundle] pathForResource:@"boing" ofType:@"wav"]];
    audioPlayer = [[AVAudioPlayer alloc] initWithContentsOfURL:soundFile error:nil];
    [audioPlayer setDelegate:self];
    [audioPlayer play];
}

- (void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration
{
    if (acceleration.x > 0.5 || acceleration.y > 0.5 || acceleration.z > 0.5) {
        [self playAudioFile];
        NSLog(@"Trigger @ 0.5x");
    }
}

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