Java ParseInt 健全性检查
我正在尝试从 String 数组元素解析 int 。这是我的代码：
String length = messageContents[k].replace("Content-Length:", "").replace(" ", "");
System.out.println("Length is: " + length);
int test= Integer.parseInt(length);
System.out.println 返回以下内容：长度为：23
但是，当我尝试将 String 解析为一个int，一个java.lang.NumberFormatException被抛出；
java.lang.NumberFormatException: For input string: "23"
我有点困惑 23 如何不会被解析为 int 。我只能假设那里有其他一些角色在阻止它，但我一生都看不到它。
有什么建议吗？
谢谢
更新
Despite the String length having only two characters, Java reports its length as three:
Length is: '23'
Length of length variable is: 3
length.getBytes = [B@126804e
I'm trying to parse a int from a String array element. Here is my code:
String length = messageContents[k].replace("Content-Length:", "").replace(" ", "");
System.out.println("Length is: " + length);
int test= Integer.parseInt(length);
The System.out.println returns the following: Length is: 23
However, when I try to parse the String into an int, a java.lang.NumberFormatException gets thrown;
java.lang.NumberFormatException: For input string: "23"
I'm a bit confused how 23 wont get parsed into an int. I can only assume that there is some other character in there that is preventing it, but I can't see it for the life of me.
Any suggestions?
Thanks
Update
Despite the String length having only two characters, Java reports its length as three:
Length is: '23'
Length of length variable is: 3
length.getBytes = [B@126804e
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尝试这个变体：
Try this variant:
该字符串中可能存在看不见的字符。
我的想法：使用带有模式/匹配器的正则表达式来删除字符串中的所有非数字，然后解析它。
There might be unseen characters in this string.
My idea: use a regex with a Pattern/Matcher to remove all the non-numerals in your string, then parse it.