python 子进程调用 OSX
我正在尝试通过 python 访问 wifi 接口： 在bash中我可以使用下面的
/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport -I
-s也可以通过。
我尝试在 python 中使用以下内容：
from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])
有些东西绝对不正确 - 正如我得到的答复：
Traceback (most recent call last):
File "ip3.py", line 5, in <module>
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 467, in call
return Popen(*popenargs, **kwargs).wait()
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 741, in __init__
restore_signals, start_new_session)
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 1356, in _execute_child
raise child_exception_type(errno_num, err_msg)
OSError: [Errno 2] No such file or directory: '/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport'
欢迎任何想法...我只想开始将其打印到屏幕上，另存为数组等...
我还没有足够高的评分来回答我自己的问题，所以我会在这里说！
所以我很愚蠢！
from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport', '-I'])
工作正常。只需删除 /usr/sbin/airport
I am trying to access the wifi interface through python:
In bash I can use the following
/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport -I
-s can also be passed.
I have tried using the following in python:
from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])
something is definitely not correct - as I get as a reply:
Traceback (most recent call last):
File "ip3.py", line 5, in <module>
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport', '-I'])
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 467, in call
return Popen(*popenargs, **kwargs).wait()
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 741, in __init__
restore_signals, start_new_session)
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/subprocess.py", line 1356, in _execute_child
raise child_exception_type(errno_num, err_msg)
OSError: [Errno 2] No such file or directory: '/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport /usr/sbin/airport'
Any ideas would be welcome... I just want to begin by printing this to screen, saving as an array etc...
I dont have a high enough rating to answer my own question yet, so Ill say it here!
so I was being stupid!
from subprocess import call
call(['/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport', '-I'])
Works fine. Just needed to remove /usr/sbin/airport
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调用将第一个参数作为命令，并使用该命令的后续参数。
在你的情况下
命令是，
/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport
和命令的两个参数是
因此，您需要将其称为，
call take first argument as command and subsequent arguments to that command.
In your case
command is,
/System/Library/PrivateFrameworks/Apple80211.framework/Versions/Current/Resources/airport
and command's two arguments are,
So, you need to call it as,
尝试这样
否则它认为
/usr/sbin/airport是第一个路径的一部分。Try like this
Otherwise it thinks
/usr/sbin/airportis part of the first path.