有没有办法包装一个像关键字一样命名的结构（例如 print ）？

发布于 2024-12-27 04:48:08 字数 385 浏览 1 评论 0原文

我有一些 C 源代码，想将其包装在 Cython 中。现在的问题是，有一个名为 print 的结构，并且 externing 它会引发语法错误。

cdef extern from "foo.h":
    struct print:
        # ...

当像关键字一样调用属性或函数等时，也会出现同样的问题。

cdef extern from "foo.h":
    struct foo:
        bint print
    print(char*, int)

有没有办法解决这个问题，无需修改源代码？也许有某种技术可以用源文件中的真实姓名替换代理名称？

原文

I have some C source code and want to wrap it in Cython. Now, the problem is, that there is a structure called print, and externing it throws a syntax error.

cdef extern from "foo.h":
    struct print:
        # ...

Same problem would appear when an attribute or a function or alike is called like a keyword.

cdef extern from "foo.h":
    struct foo:
        bint print
    print(char*, int)

Is there a way to work around this, without modifieng the source? Maybe some technique that replaces a proxy-name with the real-name in the source-file ?

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归属感 2025-01-03 04:48:08

我认为您正在寻找的解决方案类似于：

cdef extern from "foo.h":
    struct print "MY_print":
        double var "MY_var"

print.var 将被定义为：

MY_print.MY_var

这样您就可以从头文件中重命名结构、函数、联合和枚举。当 Cython 将代码编译为 C 代码时，名称会被转换。

Cython 文档的相关部分可以找到此处。

I think the solution you are looking for is something along the lines of:

cdef extern from "foo.h":
    struct print "MY_print":
        double var "MY_var"

print.var will then be defined by:

MY_print.MY_var

This way you can rename structs, functions, unions and enums from the header file. The names are converted when Cython compiles your code into C code.

The relevant part of Cython documentation can be found here.

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