bash 脚本：如何使用对话框获取无线电列表上的项目名称

发布于 2024-12-26 05:07:34 字数 280 浏览 0 评论 0原文

我需要使用对话框界面在 bash 脚本中创建一个无线电列表，例如，如果我有以下列表：

dialog --backtitle "OS information" \
--radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off

我需要当用户选择一个选项并按“确定”时，我的脚本可以读取项目的名称而不是项目的编号。

有可能吗？

谢谢！

原文

I need to make a radiolist in bash script using dialog interface, for example if I have the following list:

dialog --backtitle "OS information" \
--radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off

I need when the user chooses an option and presses "ok", my script could read the item's name and not the item's number.

It is possible?

Thanks!

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无法回应 2025-01-02 05:07:34

您可以将预期结果放入数组中：

array=(Linux Solaris HPUX)
var=$(dialog --backtitle "OS infomration" \
--radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off >/dev/tty 2>&1 )

printf '\n\nYou chose: %s\n' "${array[var - 1]}"

You can put your expected results in an array:

array=(Linux Solaris HPUX)
var=$(dialog --backtitle "OS infomration" \
--radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off >/dev/tty 2>&1 )

printf '\n\nYou chose: %s\n' "${array[var - 1]}"

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各自安好 2025-01-02 05:07:34

在 Termux 应用 > 中/dev/tty 2>&1 不起作用，但 3>&1 1>&2 2>&3 3>&- 工作正常。

这意味着：3>&1打开一个指向stdout的新文件描述符，1>&2将stdout重定向到stderr，2> &3 将 stderr 指向 stdout，并且 3>&- 在命令执行后删除文件描述符 3。

取自：BASH：变量中的对话框输入

sooo....

array=(Linux Solaris HPUX)
var=$(dialog --backtitle "OS infomration" \
 --radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off 3>&1 1>&2 2>&3 3>&- )
printf '\n\nYou chose: %s\n' "${array[$var - 1]}"

in Termux app >/dev/tty 2>&1 is not working, but 3>&1 1>&2 2>&3 3>&- is working perfectly.

which means: 3>&1 opens a new file descriptor which points to stdout, 1>&2 redirects stdout to stderr, 2>&3 points stderr to stdout and 3>&- deletes the files descriptor 3 after the command has been executed.

taken from:BASH: Dialog input in a variable

sooo....

array=(Linux Solaris HPUX)
var=$(dialog --backtitle "OS infomration" \
 --radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off 3>&1 1>&2 2>&3 3>&- )
printf '\n\nYou chose: %s\n' "${array[$var - 1]}"

回复收藏 0 原文

美人如玉 2025-01-02 05:07:34

man dialog

 --stdout
              Direct output to the standard output.  This option is provided
              for compatibility with Xdialog, however using it in portable
              scripts is not recommended, since curses normally writes its
              screen updates to the standard output.  If you use this option,
              dialog attempts to reopen the terminal so it can write to the
              display.  Depending on the platform and your environment, that
              may fail.

因此：

array=(Linux Solaris HPUX)

opt=$( dialog --stdout \
 --backtitle "OS infomration" \
 --radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off )

printf '\n\nYou chose: %s\n' "${array[var - 1]}"

man dialog

 --stdout
              Direct output to the standard output.  This option is provided
              for compatibility with Xdialog, however using it in portable
              scripts is not recommended, since curses normally writes its
              screen updates to the standard output.  If you use this option,
              dialog attempts to reopen the terminal so it can write to the
              display.  Depending on the platform and your environment, that
              may fail.

therefore:

array=(Linux Solaris HPUX)

opt=$( dialog --stdout \
 --backtitle "OS infomration" \
 --radiolist "Select OS:" 10 40 3 \
 1 "Linux 7.2" off \
 2 "Solaris 9" on \
 3 "HPUX 11i" off )

printf '\n\nYou chose: %s\n' "${array[var - 1]}"

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~没有更多了~