如何使用php变量作为java小程序的参数

发布于 2024-12-25 16:20:21 字数 811 浏览 4 评论 0原文

我想在调用java小程序时使用php会话变量作为参数。我在网上看到了这个问题的答案，但它们在我的机器上不起作用。 html 文件和小程序生成文字字符串而不是变量的内容。

这是我使用过的代码。

<param name="param1" value="<?php echo $thevar;?>" />

我也尝试过对此的变体，但无济于事

<?php echo'<param name="param1" value="$thevar" />';?>
<param name="param1" value="<?php echo($thevar);?>" />
<param name="param1" value=<?php echo $thevar;?>/>
<?php echo '<param name="param1" value=".$name1.">';?>
echo '<PARAM NAME="name" VALUE="'
. htmlspecialchars($name1, ENT_QUOTES)
. '">';

该文件是一个 html 文件。它应该是一个php文件吗？我使用相同的代码创建了一个 php 文件，但我的机器不知道使用哪个程序来运行它。它没有在 Firefox 中运行。

我在生成任何 html 之前就开始会话。

有些网站建议 HTML param 标记以 /> 结尾。还有人以 > 结尾，哪个是正确的？

我需要用反斜杠转义某些字符吗？

原文

I want to use a php session variable as a parameter when I call a java applet. I have seen answers to this on the net but they do not work on my machine. The html file and applet produce the literal string instead of the content of the variable.

Here is the code that I have used.

<param name="param1" value="<?php echo $thevar;?>" />

I have also tried variations on this to no avail

<?php echo'<param name="param1" value="$thevar" />';?>
<param name="param1" value="<?php echo($thevar);?>" />
<param name="param1" value=<?php echo $thevar;?>/>
<?php echo '<param name="param1" value=".$name1.">';?>
echo '<PARAM NAME="name" VALUE="'
. htmlspecialchars($name1, ENT_QUOTES)
. '">';

The file is an html file. Should it be a php file? I created a php file with the same code, but my machine did not know which program to use to run it. It did not run in firefox.

I start the session prior to having any html.

Some sites recommend that the HTML param tag end with /> and others end it with >, which is correct?

Do I need to escape some characters with the backslash?

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