Android setPressed 行为

发布于 2024-12-25 11:21:02 字数 281 浏览 0 评论 0原文

下面的代码尝试模拟击键：

button1.setPressed(true);
try {
Thread.sleep(500);
} catch(InterruptedException e) {
} 
button1.setPressed(false);

上面的代码对按钮没有任何作用，但

button1.setPressed(true);

它本身将按钮设置为按下状态。
为什么第一个片段对按钮没有影响？

原文

The following code is an attempt to simulate a key stroke:

button1.setPressed(true);
try {
Thread.sleep(500);
} catch(InterruptedException e) {
} 
button1.setPressed(false);

The above does nothing at all to the button, but

button1.setPressed(true);

by itself sets the button to it's pressed state.
Why does the first snippet have no effect on the button?

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格子衫的從容 2025-01-01 11:21:02

回复较晚，但我的猜测是因为您阻塞了 UI 线程，因此在您再次禁用按下状态之前它不会更新 UI。

相反，你可以尝试类似的事情；

class MyClass extends Activity ... {
  private final Handler _handler = new Handler();
  ...
  void somefunc() {
    button1.setPressed(true);
    _handler.postDelayed(new Runnable() {
      @Override
      public void run() {
        button1.setPressed(false);
      }
    }, 500);
  }
}

祝你好运！

Late reply, but my guess would be because you are blocking the UI-thread, so it will not update the UI until you've already disabled the pressed state again.

Instead you could try something like;

class MyClass extends Activity ... {
  private final Handler _handler = new Handler();
  ...
  void somefunc() {
    button1.setPressed(true);
    _handler.postDelayed(new Runnable() {
      @Override
      public void run() {
        button1.setPressed(false);
      }
    }, 500);
  }
}

Good luck!

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