如何从 Ruby 字符串中抓取文本片段？

Question

如果用户提交如下字符串：

我的客厅计划#plans #livingroom @cbmeeks #design @moe @larry - 这太酷了！

我想要以下数组/字符串：

text = "My living room plans"
tags = ['plans', 'livingroom', 'design']
people = ['cbmeeks', 'moe', 'larry']
description = "this is cool!"

提交的每个字符串都以 text 片段开头。没有 @、- 等。我不必担心用户以标签或人开头。细分应该类似于这样，可以按任何顺序排列，除了 TEXT 始终位于第一位。

TEXT [-description] [#tags] [@people]

编辑 我似乎不知道如何正确地抓住它们。例如：

a = "My living room plans #plans #livingroom @cbmeeks #design @moe @larry -this is cool!"

/#\w+/.match(a).to_a
#=> ["#plans"] -- only grabs first one

Answer 1

input = "My living room plans #plans #livingroom @cbmeeks #design @moe @larry -this is cool!"
text = input.match('^(.*?)#')[1]
tags = input.scan(/#(.*?) /)
people = input.scan(/@(.*?) /)
description = input.match('-(.*?)
)[1]

Answer 2

str = 'My living room plans #plans #livingroom @cbmeeks #design @moe @larry -this is cool!'

text = str[/^([^#\@]+)/, 1].strip # => "My living room plans"
str.sub!(text, '') # => " #plans #livingroom @cbmeeks #design @moe @larry -this is cool!"

tags        = str.scan( /#([a-z0-9]+)/ ).flatten # => ["plans", "livingroom", "design"]
people      = str.scan( /@([a-z0-9]+)/ ).flatten # => ["cbmeeks", "moe", "larry"]
description = str.scan( /-(.+)/        ).flatten # => ["this is cool!"]

Answer 3

这将自动删除 #、@、-，并以任意顺序匹配：

string = "My living room plans #plans #livingroom @cbmeeks #design @moe @larry -this is cool!"
text = string[/^(.*?)+(?=\s[@#-])/]
tags = string.scan /(?<=#)\w+/
people = string.scan /(?<=@)\w+/
description = string[/(?<=-)(.*?)+?(?=($|\s[@#]))/]