如何处理 '[<__nscfstring 0x2f1730>valueForUndefinedKey:]: 此类对于键 $oid' 来说不符合键值编码。错误

发布于 2024-12-24 23:02:16 字数 509 浏览 2 评论 0原文

我遇到了错误（主题中所述），因为有时属性“id”不会在返回的 json 中存储包含“$oid”的哈希。例如

，有时我得到：

"id":{"$oid":"4eea972209f47a0028000140"}

有时我得到

"id":"4eea972209f47a0028000140"

我试图在以下代码中进行检查以适应这种不规则性

if ([[question valueForKey:@"id"] valueForKey:@"$oid"])
{
    question_id = [[question valueForKey:@"id"] valueForKey:@"$oid"];
}
else
{
    question_id = [question valueForKey:@"id"];
}

但是，它仍然不起作用，因为代码在检查阶段失败。

如何实施检查，以便仅在“$oid”存在时才从“$oid”中获取 Question_id？

原文

I am hitting the error (stated in the subject) because there are times the property 'id' does not store the hash containing '$oid' in the returned json. For example

Sometimes I get:

"id":{"$oid":"4eea972209f47a0028000140"}

Some other times I get

"id":"4eea972209f47a0028000140"

I am trying to do a check in the following code to cater for such irregularity

if ([[question valueForKey:@"id"] valueForKey:@"$oid"])
{
    question_id = [[question valueForKey:@"id"] valueForKey:@"$oid"];
}
else
{
    question_id = [question valueForKey:@"id"];
}

However, it still doesn't work as the code fails during the checking phase.

How can I implement a check so that I will take question_id from '$oid' only if it exists?

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尛丟丟 2024-12-31 23:02:16

尝试以下代码。

id quesDict = [question valueForKey:@"id"];
if( [quesDict isKindOfClass:[NSDictionary class]] )
{
    question_id = [quesDict valueForKey:@"$oid"];
}
else
{
    question_id = quesDict;
}

Try the following code.

id quesDict = [question valueForKey:@"id"];
if( [quesDict isKindOfClass:[NSDictionary class]] )
{
    question_id = [quesDict valueForKey:@"$oid"];
}
else
{
    question_id = quesDict;
}

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