Django 元管理排序 - 排除语法文章

发布于 2024-12-24 20:33:54 字数 710 浏览 2 评论 0原文

我目前有这样的模型代码块：

class Book(models.Model):
    title = models.CharField(max_length=100)
    num_pages = models.IntegerField(blank=True, null=True)
    authors = models.ManyToManyField(Author)
    publisher = models.ForeignKey(Publisher)
    publication_date = models.DateField()

    def __unicode__(self):
        return self.title

    class Meta:
        ordering = ["title"]

如果我有一本名为“The Fry Chronicles”或“A Hitchhikers Guide to the Galaxy”（例如）的书名，则为有没有办法让 Django 忽略管理界面中单词之前的那些短文章（an、a、the 等），而只按文章后面的单词对结果进行排序？

更进一步，也许有一种方法可以像这样排列结果......

弗莱编年史，
银河系漫游指南，A

至于将文章移到书名的末尾吗？

有人可以提出解决上述两个问题的方案吗？

提前致谢！

原文

I currently have this chunk of model code:

class Book(models.Model):
    title = models.CharField(max_length=100)
    num_pages = models.IntegerField(blank=True, null=True)
    authors = models.ManyToManyField(Author)
    publisher = models.ForeignKey(Publisher)
    publication_date = models.DateField()

    def __unicode__(self):
        return self.title

    class Meta:
        ordering = ["title"]

If I have a book title called 'The Fry Chronicles' or 'A Hitchhikers Guide to the Galaxy' (for example), is there a way to get Django to ignore those short articles (an, a, the etc.) before the word within the admin interface, and just order the results by the words that follows the article?

To take it a step further, maybe there is a way to lay out the results like this...

Fry Chronicles, The
Hitchhikers Guide to the Galaxy, A

As to move the article to the end of the book title?

Could anybody propose a solution to the above two issues?

Thanks in advance!

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夏末的微笑 2024-12-31 20:33:54

您可以尝试，

class Book(models.Model):
    displayed_title = models.CharField(max_length=100)
    ordered_title = models.CharField(max_length=100)

    def __unicode__(self):
        return self.displayed_title

    class Meta:
        ordering = ["ordered_title"]

并且只需确保在存储之前解析 ordered_title 即可。

You could try,

class Book(models.Model):
    displayed_title = models.CharField(max_length=100)
    ordered_title = models.CharField(max_length=100)

    def __unicode__(self):
        return self.displayed_title

    class Meta:
        ordering = ["ordered_title"]

And just make sure that you are parsing ordered_title before you store it.

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最近可好 2024-12-31 20:33:54

我认为如果不破解内部 django 管理代码，这是不可能的。

不过，如果冗余不是问题，您可以采取一些小技巧。 Book 中有额外的字段，表示订购的标题（如 clean_title）和使用 ordering 管理中的属性。

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酒绊 2024-12-31 20:33:54

不知道这是否有效...未经测试...只是一个想法，请记住 django 只是 python...我希望这有助于让您走上正轨！？！

def splitter(title):  
    list_title=[]
    a = split(title)    
        for word in a:
            if len(word) > 3: # With this you filter "a" "the" etc. but not "Bob" etc.!!
               word.append(list_title)
    return list_tile


class Meta:
    ordering = splitter(title) # not sure if this is working....

Don't know if this is working....untested...just an idea to keep in mind that django is just python...I hope that helps to get you to the right track!?!

def splitter(title):  
    list_title=[]
    a = split(title)    
        for word in a:
            if len(word) > 3: # With this you filter "a" "the" etc. but not "Bob" etc.!!
               word.append(list_title)
    return list_tile


class Meta:
    ordering = splitter(title) # not sure if this is working....

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