iOS 上的高精度随机数
我已经尝试了一段时间，但到目前为止还没有任何运气。
在 iOS 上检索两个非常精确的数字之间的随机数的最简单方法是什么？
例如，我想要一个介于 41.37783830549337 和 41.377730629131634 之间的随机数，我该如何实现呢？
提前非常感谢！
编辑：我尝试了这个：
double min = 41.37783830549337;
double max = 41.377730629131634;
double test = ((double)rand() / RAND_MAX) * (max - min) + min;
NSLog(@"Min:%lf, max:%lf, result:%lf",min,max,test);
但结果并不像我希望的那么精确，结果是这样的::
Min:41.377838, max:41.377731, result:41.377838
I have been trying this for a while but thus far haven't had any luck.
What is the easiest way to retrieve a random number between two very precise numbers on iOS?
For example, I want a random number between 41.37783830549337 and 41.377730629131634, how would I accomplish this?
Thank you so much in advance!
Edit: I tried this:
double min = 41.37783830549337;
double max = 41.377730629131634;
double test = ((double)rand() / RAND_MAX) * (max - min) + min;
NSLog(@"Min:%lf, max:%lf, result:%lf",min,max,test);
But the results weren't quite as precise as I was hoping, and ended up like this::
Min:41.377838, max:41.377731, result:41.377838
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您可以将
rand的输出标准化为您想要的任何范围：[注意：这是纯 C，我假设它在 Obj-C 中等效工作。]
[< em>注释 2：将
double替换为您选择的适当数据类型。][注释 3：将
rand替换为 random-您根据情况选择号码来源。]You can normalise the output of
randto any range you want:[Note: This is pure C, I'm assuming it works equivalently in Obj-C.]
[Note 2: Replace
doublewith the data-type of your choice as appropriate.][Note 3: Replace
randwith the random-number source of your choice as appropriate.]