如何枚举 CGPoints 的 nsmutablearray？

发布于 2024-12-24 03:36:53 字数 635 浏览 2 评论 0原文

这是我的代码：

for (NSValue * i in cgpointarray){
        [text setHidden:NO];
        CGPoint temppoint = i.CGPointValue;
         if (touchended.x < temppoint.x+36 && touchended.x > temppoint.x-36 && touchended.y < temppoint.y+36 && touchended.y > temppoint.y -36){
             spacetouched = i;
             break;
        }

目的是搜索每个空间（数组的 cgpoint x）+或- 36 像素以查找触摸的 CGPoint。但是，我创建了一个名为 text 的标签并将其设置为隐藏，当此代码运行时，文本标签不会显示，因此我认为它没有执行代码。如果有什么区别的话， cgpointarray 是一个 NSMutableArray 。

编辑：在这一行：CGPoint temppoint = i.CGPointValue;编译器说：'i'的本地声明隐藏了实例变量

原文

Here is the code I have:

for (NSValue * i in cgpointarray){
        [text setHidden:NO];
        CGPoint temppoint = i.CGPointValue;
         if (touchended.x < temppoint.x+36 && touchended.x > temppoint.x-36 && touchended.y < temppoint.y+36 && touchended.y > temppoint.y -36){
             spacetouched = i;
             break;
        }

The purpose is to search each space (cgpoint x of array) +or- 36 pixels for the touchended CGPoint. However I have created a label named text and set it to hidden, when this code runs the text label does not show up, therefore I think that it is not executing the code. The cgpointarray is an NSMutableArray if that makes any difference.

edit: on this line: CGPoint temppoint = i.CGPointValue; the compiler says: local declaration of 'i' hides instance variable

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