如何在 c# windows 8 中将简单的流（http webresponse）转换为位图图像？

Question

我尝试了 1000 次，将一个简单的流（http webresponse）转换为位图图像，但没有一个教程可以在 c# windows 8 中工作。

示例：

BitmapImage image = new BitmapImage();
image.SetSource(stream);
image1.Source = image; 

感谢所有回复。

解决方案

InMemoryRandomAccessStream randomAccessStream = new InMemoryRandomAccessStream();
DataWriter writer = new DataWriter(randomAccessStream.GetOutputStreamAt(0));
writer.WriteBytes((byte[])command);
await writer.StoreAsync();
BitmapImage image = new BitmapImage();
image.SetSource(randomAccessStream);

Answer 1

试试这个代码：

private async Task GetLocalImageAsync(string internetUri, string folderName, 
                                      string uniqueName)
{
    using (var response = await HttpWebRequest.CreateHttp(internetUri)
                                .GetResponseAsync())
    {
        using (var stream = response.GetResponseStream())
        {
            var folder = await ApplicationData.Current.LocalFolder
                               .CreateFolderAsync(folderName, 
                                        CreationCollisionOption.OpenIfExists);
            var file = await folder.CreateFileAsync(
                                    string.Format("{0}", uniqueName),
                                    CreationCollisionOption.ReplaceExisting);
            using (var filestream = await file.OpenStreamForWriteAsync())
            {
                await stream.CopyToAsync(filestream);
                await filestream.FlushAsync();
            }
        }
    }
}

Answer 2

你试过这个吗？

InMemoryRandomAccessStream randomAccessStream = new InMemoryRandomAccessStream();
DataWriter writer = new DataWriter(randomAccessStream.GetOutputStreamAt(0));
writer.WriteBytes(response.Content.ReadAsByteArray());
BitmapImage image = new BitmapImage();
image.SetSource(randomAccessStream);