无法使用二进制阅读器读取打开的文件
我有这个函数来读取 SQL Server 错误日志,但问题是我无法读取服务器当时使用的错误日志。我一直在谷歌搜索,似乎 Fileshare 标志不适用于 powershell。当我尝试打开文件时,有什么方法可以设置文件共享标志吗?
function check_logs{ param($logs) $pos foreach($log in $logpos){ if($log.host -eq $logs.host){ $currentLog = $log break } } if($currentLog -eq $null){ $currentLog = @{} $logpos.Add($currentLog) $currentLog.host = $logs.host $currentLog.event = $logs.type $currentLog.lastpos = 0 } $path = $logs.file if($currentLog.lastpos -ne $null){$pos = $currentLog.lastpos} else{$pos = 0} if($logs.enc -eq $null){$br = New-Object System.IO.BinaryReader([System.IO.File]::Open($path, [System.IO.FileMode]::Open))} else{ $encoding = $logs.enc.toUpper().Replace('-','') if($encoding -eq 'UTF16'){$encoding = 'Unicode'} $br = New-Object System.IO.BinaryReader([System.IO.File]::Open($path, [System.IO.FileMode]::Open), [System.Text.Encoding]::$encoding) } $required = $br.BaseStream.Length - $pos if($required -lt 0){ $pos = 0 $required = $br.BaseStream.Length } if($required -eq 0){$br.close(); return $null} $br.BaseStream.Seek($pos, [System.IO.SeekOrigin]::Begin)|Out-Null $bytes = $br.ReadBytes($required) $result = [System.Text.Encoding]::Unicode.GetString($bytes) $split = $result.Split("`n") foreach($s in $split) { if($s.contains(" Error:")) { $errorLine = [regex]::Split($s, "\s\s+") $err = [regex]::Split($errorLine[1], "\s+") if(log_filter $currentLog.event $err[1..$err.length]){$Script:events = $events+ [string]$s + "`n" } } } $currentLog.lastpos = $br.BaseStream.Position $br.close() }
需要明确的是,当我尝试打开文件时会出现错误。错误消息是:
Exception calling "Open" with "2" argument(s): "The process cannot access the file
'C:\Program Files\Microsoft SQL Server\MSSQL10.MSSQLSERVER\MSSQL\Log\ERRORLOG'
because it is being used by another process."
Gísli
I have this function to read the SQL Server errorlog but the problem is that I'm not able to read the errorlog that the server is using at the time. I have been google-ing and it seems that the Fileshare flag isn't working for powershell. Is there some way to set the the Fileshare flag when I try to open the file?
function check_logs{ param($logs) $pos foreach($log in $logpos){ if($log.host -eq $logs.host){ $currentLog = $log break } } if($currentLog -eq $null){ $currentLog = @{} $logpos.Add($currentLog) $currentLog.host = $logs.host $currentLog.event = $logs.type $currentLog.lastpos = 0 } $path = $logs.file if($currentLog.lastpos -ne $null){$pos = $currentLog.lastpos} else{$pos = 0} if($logs.enc -eq $null){$br = New-Object System.IO.BinaryReader([System.IO.File]::Open($path, [System.IO.FileMode]::Open))} else{ $encoding = $logs.enc.toUpper().Replace('-','') if($encoding -eq 'UTF16'){$encoding = 'Unicode'} $br = New-Object System.IO.BinaryReader([System.IO.File]::Open($path, [System.IO.FileMode]::Open), [System.Text.Encoding]::$encoding) } $required = $br.BaseStream.Length - $pos if($required -lt 0){ $pos = 0 $required = $br.BaseStream.Length } if($required -eq 0){$br.close(); return $null} $br.BaseStream.Seek($pos, [System.IO.SeekOrigin]::Begin)|Out-Null $bytes = $br.ReadBytes($required) $result = [System.Text.Encoding]::Unicode.GetString($bytes) $split = $result.Split("`n") foreach($s in $split) { if($s.contains(" Error:")) { $errorLine = [regex]::Split($s, "\s\s+") $err = [regex]::Split($errorLine[1], "\s+") if(log_filter $currentLog.event $err[1..$err.length]){$Script:events = $events+ [string]$s + "`n" } } } $currentLog.lastpos = $br.BaseStream.Position $br.close() }
To be clear the error comes when I try to open the file. The error message is:
Exception calling "Open" with "2" argument(s): "The process cannot access the file
'C:\Program Files\Microsoft SQL Server\MSSQL10.MSSQLSERVER\MSSQL\Log\ERRORLOG'
because it is being used by another process."
Gísli
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
所以我找到了答案,而且非常简单。
二进制读取器构造函数将流作为输入。我没有单独定义流,这就是为什么我没有注意到您在流的构造函数中设置了 FileShare 标志。
我要做的就是改变这个:
到这个:
然后它就像一个魅力。
吉斯利
So I found the answer and it was pretty simple.
The binary reader constructor takes as input a stream. I didn't define the stream seperately and that's why I didn't notice that you set the FileShare flag in the stream's constructor.
What I had to do was to change this:
To this:
And then it worked like a charm.
Gísli