从 JavaScript 中的 URL 中删除查询参数

发布于 2024-12-23 18:33:35 字数 876 浏览 0 评论 0原文

我正在尝试编写一个函数，该函数将从 javascript 中的 url 中删除查询参数。我想我使用正则表达式来实现它，但我不确定我是否错过了任何东西。另外，我无法摆脱这种感觉，可能有更好的方法来做到这一点，而不需要我花半天时间摆弄正则表达式，并且冒着后来发现我没有采取某种角落的风险情况考虑在内。

remove_query_argument = function(url, arg){

    var query_arg_regex;

    // Remove occurences that come after '&' symbols and not the first one after the '?'
    query_arg_regex = new RegExp('&' + arg + '=[^(?:&|$)]*', 'ig');
    url = url.replace(query_arg_regex, '');

    // remove the instance that the argument to remove is the first one
    query_arg_regex = new RegExp('[?]' + arg + '[^(?:&|$)]*(&?)', 'i');
    url = url.replace(query_arg_regex, function (match, capture) {
        if( capture != '&' ){
            return '';
        }else{
            return '?'
        }

    });

    return url;
}

有没有人看到这段代码有任何问题，或者想建议更好的实现或方法来解决这个问题？

谢谢！

原文

I'm trying to write a function that will remove a query argument from a url in javascript. I think I have it using regex, but I'm not sure if I've missed anything. Also, I can't shake the feeling that there was probably a better way to do this that didn't involve me messing around with regex half the day and running the risk of later finding out that I didn't take some kind of corner case into account.

remove_query_argument = function(url, arg){

    var query_arg_regex;

    // Remove occurences that come after '&' symbols and not the first one after the '?'
    query_arg_regex = new RegExp('&' + arg + '=[^(?:&|$)]*', 'ig');
    url = url.replace(query_arg_regex, '');

    // remove the instance that the argument to remove is the first one
    query_arg_regex = new RegExp('[?]' + arg + '[^(?:&|$)]*(&?)', 'i');
    url = url.replace(query_arg_regex, function (match, capture) {
        if( capture != '&' ){
            return '';
        }else{
            return '?'
        }

    });

    return url;
}

Does anyone see any problems with this code or would like to suggest a better implementation or way of going about this?

Thanks!

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打小就很酷 2024-12-30 18:33:35

如果你有很多与 URL 相关的操作，你最好尝试一下这个很棒的 js 库 https://github.com /medialize/URI.js

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锦爱 2024-12-30 18:33:35

给定一个百分比编码 URL，以下函数将从其查询中删除字段值对字符串：

var removeQueryFields = function (url) {
    var fields = [].slice.call(arguments, 1).join('|'),
        parts = url.split( new RegExp('[&?](' + fields + ')=[^&]*') ),
        length = parts.length - 1;
    return parts[0] + '?' + (length ? parts[length].slice(1) : '');
}

一些示例：

var string = 'http://server/path/program?f1=v1&f2=v2';
removeQueryFields( string, 'f1' );       // 'http://server/path/program?f2=v2'
removeQueryFields( string, 'f2' );       // 'http://server/path/program?f1=v1'
removeQueryFields( string, 'f1', 'f2' ); // 'http://server/path/program'

Given a percent-encoded URL, the following function will remove field-value pairs from its query string:

var removeQueryFields = function (url) {
    var fields = [].slice.call(arguments, 1).join('|'),
        parts = url.split( new RegExp('[&?](' + fields + ')=[^&]*') ),
        length = parts.length - 1;
    return parts[0] + '?' + (length ? parts[length].slice(1) : '');
}

Some examples:

var string = 'http://server/path/program?f1=v1&f2=v2';
removeQueryFields( string, 'f1' );       // 'http://server/path/program?f2=v2'
removeQueryFields( string, 'f2' );       // 'http://server/path/program?f1=v1'
removeQueryFields( string, 'f1', 'f2' ); // 'http://server/path/program'

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