前导“@”是什么？根据 makefile 的配方

发布于 2024-12-23 15:29:39 字数 600 浏览 2 评论 0原文

在 eclipse 生成的 makefile 中，我看到以下规则：

./Cores/$(TARGET).core.3.srec : ../$(TARGET).core.3/Debug/$(TARGET).core.3.elf
        @mkdir -p ./Cores/
        @e-objcopy --srec-forceS3 --output-target srec "$<" "$@".temp
        @echo Creating srec file for CoreID\<0x826\>
        @head --lines=1 "$@".temp  | sed 's/0000/0826/' > "$@"
        @tail --lines=+2 "$@".temp >> "$@"

配方行开头的“@”的用途是什么？

通读 GNU Make 用户手册，我找不到对 @ 的使用的引用。然后我假设它实际上按原样转移到外壳。

因此，在阅读 BASH 手册时，我唯一能想到这种用法的地方是设置 extglob 选项时的命令替换。但是，在命令行中尝试此操作给了我一个错误。

原文

In a makefile that is generated by eclipse, I see the following rules:

./Cores/$(TARGET).core.3.srec : ../$(TARGET).core.3/Debug/$(TARGET).core.3.elf
        @mkdir -p ./Cores/
        @e-objcopy --srec-forceS3 --output-target srec "lt;" "$@".temp
        @echo Creating srec file for CoreID\<0x826\>
        @head --lines=1 "$@".temp  | sed 's/0000/0826/' > "$@"
        @tail --lines=+2 "$@".temp >> "$@"

What is the purpose of the "@" at the beginning of the recipe lines?

Reading through the GNU Make user's manual I could not find a reference to this use of @. I then assumed that it is actually transferred as-is to the shell.

So, reading the BASH manual, the only place I could relate to this use is in command substitution when the extglob option is set. However, trying this in the command line gave me an error.

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