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Python-Matplotlib 箱线图。如何显示百分位数 0、10、25、50、75、90 和 100？

发布于 2024-12-23 15:23:14 字数 414 浏览 2 评论 0原文

我想绘制一个 EPSgram （见下文）使用 Python 和 Matplotlib。

boxplot 函数仅绘制四分位数（ 0、25、50、75、100）。那么，如何再添加两个盒子呢？

EPSGram 箱线图

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沒落の蓅哖 2024-12-30 15:23:14

如果你仍然好奇的话，我整理了一个样本。它使用 scipy.stats.scoreatpercentile，但您可能会从其他地方获取这些数字：

from random import random
import numpy as np
import matplotlib.pyplot as plt
from scipy.stats import scoreatpercentile

x = np.array([random() for x in xrange(100)])

# percentiles of interest
perc = [min(x), scoreatpercentile(x,10), scoreatpercentile(x,25),
               scoreatpercentile(x,50), scoreatpercentile(x,75),
               scoreatpercentile(x,90), max(x)]
midpoint = 0 # time-series time

fig = plt.figure()
ax = fig.add_subplot(111)
# min/max
ax.broken_barh([(midpoint-.01,.02)], (perc[0], perc[1]-perc[0]))
ax.broken_barh([(midpoint-.01,.02)], (perc[5], perc[6]-perc[5]))
# 10/90
ax.broken_barh([(midpoint-.1,.2)], (perc[1], perc[2]-perc[1]))
ax.broken_barh([(midpoint-.1,.2)], (perc[4], perc[5]-perc[4]))
# 25/75
ax.broken_barh([(midpoint-.4,.8)], (perc[2], perc[3]-perc[2]))
ax.broken_barh([(midpoint-.4,.8)], (perc[3], perc[4]-perc[3]))

ax.set_ylim(-0.5,1.5)
ax.set_xlim(-10,10)
ax.set_yticks([0,0.5,1])
ax.grid(True)
plt.show()

I put together a sample, if you're still curious. It uses scipy.stats.scoreatpercentile, but you may be getting those numbers from elsewhere:

from random import random
import numpy as np
import matplotlib.pyplot as plt
from scipy.stats import scoreatpercentile

x = np.array([random() for x in xrange(100)])

# percentiles of interest
perc = [min(x), scoreatpercentile(x,10), scoreatpercentile(x,25),
               scoreatpercentile(x,50), scoreatpercentile(x,75),
               scoreatpercentile(x,90), max(x)]
midpoint = 0 # time-series time

fig = plt.figure()
ax = fig.add_subplot(111)
# min/max
ax.broken_barh([(midpoint-.01,.02)], (perc[0], perc[1]-perc[0]))
ax.broken_barh([(midpoint-.01,.02)], (perc[5], perc[6]-perc[5]))
# 10/90
ax.broken_barh([(midpoint-.1,.2)], (perc[1], perc[2]-perc[1]))
ax.broken_barh([(midpoint-.1,.2)], (perc[4], perc[5]-perc[4]))
# 25/75
ax.broken_barh([(midpoint-.4,.8)], (perc[2], perc[3]-perc[2]))
ax.broken_barh([(midpoint-.4,.8)], (perc[3], perc[4]-perc[3]))

ax.set_ylim(-0.5,1.5)
ax.set_xlim(-10,10)
ax.set_yticks([0,0.5,1])
ax.grid(True)
plt.show()

Output of the code above