Python中交换2个数组元素的位置

发布于 2024-12-23 13:50:37 字数 450 浏览 2 评论 0原文

有没有简单的方法可以交换数组中 2 个元素（或者更好的是 n 个元素）的位置？

我想出了一些代码，但它看起来很丑陋，而且性能应该有点差：

chromo = [[1,2], [3,4], [5,6]]

gene1Pos = random.randrange(0, len(chromo)-1, 1)
gene2Pos = random.randrange(0, len(chromo)-1, 1)
tmpGene1 = chromo[gene1Pos]
tmpGene2 = chromo[gene2Pos]
chromo[gene1Pos] = tmpGene2
chromo[gene2Pos] = tmpGene1

这应该可行，但是，这并不好。更好的方法是像 random.shuffle 这样的例程，但不是混合所有内容，而是只混合 n 个元素。你有什么想法吗？

原文

Is there any easy way to exchange the position of 2 elements - or better yet, n elements - in an array?

I came up with some code, but it looks quite ugly and the performance should be a bit bad:

chromo = [[1,2], [3,4], [5,6]]

gene1Pos = random.randrange(0, len(chromo)-1, 1)
gene2Pos = random.randrange(0, len(chromo)-1, 1)
tmpGene1 = chromo[gene1Pos]
tmpGene2 = chromo[gene2Pos]
chromo[gene1Pos] = tmpGene2
chromo[gene2Pos] = tmpGene1

This should work, but well, it's not nice. The better way would be a routine like random.shuffle but that instead of mixing everything would mix just a number n of elements. Do you have any idea?

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时常饿 2024-12-30 13:50:37

尝试

>>> chromo[gene1Pos], chromo[gene2Pos] = chromo[gene2Pos], chromo[gene1Pos]

所以你只需要确保你有正确的 genXPos

try

>>> chromo[gene1Pos], chromo[gene2Pos] = chromo[gene2Pos], chromo[gene1Pos]

So you just need to make sure you have the right genXPos

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醉梦枕江山 2024-12-30 13:50:37

只需将 Python 中交换变量的正常机制与切片/切片赋值结合起来即可。

>>> a = [1, 2, 3, 4, 5]
>>> a[2:3], a[4:5] = a[4:5], a[2:3]
>>> a
[1, 2, 5, 4, 3]

Just combine the normal mechanism for swapping variables in Python with slicing/slice assignment.

>>> a = [1, 2, 3, 4, 5]
>>> a[2:3], a[4:5] = a[4:5], a[2:3]
>>> a
[1, 2, 5, 4, 3]

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我很OK 2024-12-30 13:50:37

你所做的事情没有任何问题。不过，您可以通过删除临时变量之一来简化它。要交换 a 和 b，您所需要做的就是：

tmp = a
a = b
b = tmp

There's nothing wrong with what you're doing. You can simplify it by removing one of the temp variables though. To swap a and b, all you need is this: