unix 管道命令与 find 的混合
要获取“compact”目录中包含“measure_remove”一词的文件名， 我发出了这个命令。
find ./compact/ -type f -exec grep -n 'measure_remove' {} \ -exec ls {} \;
- grep: ls: '没有这样的文件或目录'
- grep: -exec: '没有这样的文件或目录'
- ./compact/prepare.js:44509: = "measure_remove";
- grep : ls: '没有这样的文件或目录'
- grep: -exec: '没有这样的文件或目录'
它可以工作，但我只想获取文件名和结果。 有不止一种方法吗？
To get file names which contains the word 'measure_remove' in 'compact' directory,
I made this command.
find ./compact/ -type f -exec grep -n 'measure_remove' {} \ -exec ls {} \;
- grep: ls: 'there are no such file or directory'
- grep: -exec: 'there are no such file or directory'
- ./compact/prepare.js:44509: = "measure_remove";
- grep: ls: 'there are no such file or directory'
- grep: -exec: 'there are no such file or directory'
It works but i just want to get file names and result.
is there more than one way?
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如果您只想匹配文件名，请将 -l (el) 传递给 grep：
$ find compact -type f -exec grep -l 'measure_remove' {} \;如果您还希望行匹配，某些 grep 接受 -H，但如果您给它 2 个文件名，则所有 grep 都应该打印文件名。一种常见的技术是将 /dev/null 作为第二个文件传递以进行搜索：
$ find compact -type f -exec grep -n measure_remove /dev/null {} \;If you just want the filenames that match, pass -l (el) to grep:
$ find compact -type f -exec grep -l 'measure_remove' {} \;If you also want the line matches, some grep accept -H, but all grep should print the file name if you give it 2 file names. A common technique is to pass /dev/null as a second file to search:
$ find compact -type f -exec grep -n measure_remove /dev/null {} \;