如何摆脱除法运算符？
我应该写什么才能摆脱除法运算符，而不是写“/6”？
int a ;
c = a / 6 ;
如果您对这个主题了解更多，您能给我当 b != 2 的倍数时的通用算法吗？
例如：
b = 1, 3, 5, 6, 7, 9, 10 等
Instead of writing " / 6 ", what should I write so that I can get rid of division operator ?
int a ;
c = a / 6 ;
If you know more on that topic, can you give me general algorithm when b != multiple of 2 ?
ex :
b = 1, 3, 5, 6, 7, 9, 10 , etc
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好吧，移位和减法（将
/替换为>>和可选的-的一般形式，通常用于 power-of -2 除数）是 int 的除法运算，所以我不确定您应该如何消除它。如果他们说用模数（%）替换它，我会发现他们很难认真对待。对于float或double，您可以尝试乘以倒数（这会将除法移到编译时而不是运行时），只要您不丢失精度太高，但是对于不采用定点表示的整数类型来说，这会更棘手。Well, shift-and-subtract (the general form of replacing
/with>>and optionally-, commonly seen for power-of-2 divisors) is what the division operation does for anint, so I'm not sure how you'd be expected to eliminate it. If they say to replace it with modulus (%), I'd find them hard to take seriously. Forfloatordouble, you could try multiplication by the reciprocal (which moves the division into compile-time instead of run-time), so long as you don't lose too much precision, but that's trickier for integral types without resorting to fixed point representation.