在 python 中运行 shell 脚本

发布于 2024-12-22 12:51:55 字数 867 浏览 1 评论 0原文

我需要执行一个 shell 脚本来通过 python 命令运行 python 程序。

我应该像这样执行我的 python 脚本

ubuntu@ip-10-32-157-231:~/hg_intcen/lib$ xvfb-run python webpage_scrapper.py  http://www.google.ca/search?q=navaspot

这个脚本需要在 python 程序中执行，因为必须将巨大的链接传递给该模块。

我已经搜索过在 python 中执行这个 shell 脚本，所以我使用了“subprocess”

主要是当你运行这个 shell 命令时，需要一些时间才能返回结果。我需要 python 模块来执行这个命令，并且它必须等待一段时间才能返回结果。这是必需的。

我使用了 subprocess.Popen 它不会返回像我从上面的 bash 中得到的结果那样

import subprocess
def execute_scrapping(url):
   exe_cmd = "xvfb-run python lib/webpage_scrapper.py"+" "+str(url)
   print "cmd:"+exe_cmd
   proc = subprocess.Popen(exe_cmd,shell=True,stdin=subprocess.PIPE,stdout=subprocess.PIPE)
   time.sleep(15)
   sys.stdout.flush()
   d=proc.stdout.readlines()
   return d[1]

不会得到确切的结果。你能建议我通过 python 执行 bash shell 命令并得到结果吗？

原文

I need to execute a shell script to run the python program in via python command.

I should have to execute my python script like this

ubuntu@ip-10-32-157-231:~/hg_intcen/lib$ xvfb-run python webpage_scrapper.py  http://www.google.ca/search?q=navaspot

This script need to be executed in python program since there are huge links has to be passed to that module.

I have searched to execute this shell script in python,so i used "subprocess"

The main thing is when you run this shell command it takes some time to return the result.
i need the python module to execute this command as well as it has to wait for while to return the result.This is required.

I used subprocess.Popen it doesn't return the result like what i got from the bash

import subprocess
def execute_scrapping(url):
   exe_cmd = "xvfb-run python lib/webpage_scrapper.py"+" "+str(url)
   print "cmd:"+exe_cmd
   proc = subprocess.Popen(exe_cmd,shell=True,stdin=subprocess.PIPE,stdout=subprocess.PIPE)
   time.sleep(15)
   sys.stdout.flush()
   d=proc.stdout.readlines()
   return d[1]

this above is not run into exact result.
Could you please suggest me to execute the bash shell command via python and get the result?

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浅笑依然 2024-12-29 12:51:55

尝试：

proc.wait()

而不是您的 time.sleep(15) 调用。

来自文档：

Popen.wait() - 等待子进程终止。设置并返回 returncode 属性。

Try:

proc.wait()

instead of your time.sleep(15) call.

From the docs:

Popen.wait() - Wait for child process to terminate. Set and return returncode attribute.

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<逆流佳人身旁 2024-12-29 12:51:55

您应该使用communicate() > 等待外部进程完成的方法。

stddata, stderr = proc.communicate()

如果您必须在两个进程之间交换消息，请查看 pexpect 模块：

从网站：

   import pexpect
   child = pexpect.spawn ('ftp ftp.openbsd.org')
   child.expect ('Name .*: ')
   child.sendline ('anonymous')
   child.expect ('Password:')
   child.sendline ('[email protected]')
   child.expect ('ftp> ')
   child.sendline ('cd pub')
   child.expect('ftp> ')
   child.sendline ('get ls-lR.gz')
   child.expect('ftp> ')
   child.sendline ('bye')

You should use the communicate() method to wait that the external process completes.

stddata, stderr = proc.communicate()

If you have to exchange messages between the two process then look into the pexpect module:

From the website:

   import pexpect
   child = pexpect.spawn ('ftp ftp.openbsd.org')
   child.expect ('Name .*: ')
   child.sendline ('anonymous')
   child.expect ('Password:')
   child.sendline ('[email protected]')
   child.expect ('ftp> ')
   child.sendline ('cd pub')
   child.expect('ftp> ')
   child.sendline ('get ls-lR.gz')
   child.expect('ftp> ')
   child.sendline ('bye')

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