如何为 UITableView 建立索引？

Question

我在 UITableView 的索引中较新。 我有一些演示数据，例如，

tableDataArray = [[NSMutableArray alloc] init];

NSMutableDictionary *dict = [[NSMutableDictionary alloc] init];
[dict setObject:[NSString stringWithFormat:@"Thomas Cook"] forKey:@"Name"];
[dict setObject:[NSString stringWithFormat:@"Dean"] forKey:@"Position"];
[dict setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict setObject:[NSString stringWithFormat:@"67-876-65433"] forKey:@"PhoneNo"];
[tableDataArray addObject:dict];

NSMutableDictionary *dict1 = [[NSMutableDictionary alloc] init];
[dict1 setObject:[NSString stringWithFormat:@"John Appleseed"] forKey:@"Name"];
[dict1 setObject:[NSString stringWithFormat:@"Department of accounting"] forKey:@"Position"];
[dict1 setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict1 setObject:[NSString stringWithFormat:@"45-876-65433"] forKey:@"PhoneNo"];
 [tableDataArray addObject:dict1];

NSMutableDictionary *dict2 = [[NSMutableDictionary alloc] init];
[dict2 setObject:[NSString stringWithFormat:@"Amar Smith"] forKey:@"Name"];
[dict2 setObject:[NSString stringWithFormat:@"Department of Human Resource"] forKey:@"Position"];
[dict2 setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict2 setObject:[NSString stringWithFormat:@"54-876-65433"] forKey:@"PhoneNo"];
[tableDataArray addObject:dict2];

NSMutableDictionary *dict3 = [[NSMutableDictionary alloc] init];
[dict3 setObject:[NSString stringWithFormat:@"Mary Cold"] forKey:@"Name"];
[dict3 setObject:[NSString stringWithFormat:@"HOD of Computer Department"] forKey:@"Position"];
[dict3 setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict3 setObject:[NSString stringWithFormat:@"52-876-65433"] forKey:@"PhoneNo"];
[tableDataArray addObject:dict3];

NSMutableDictionary *dict4 = [[NSMutableDictionary alloc] init];
[dict4 setObject:[NSString stringWithFormat:@"John Jobs"] forKey:@"Name"];
[dict4 setObject:[NSString stringWithFormat:@"Department of Physics"] forKey:@"Position"];
[dict4 setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict4 setObject:[NSString stringWithFormat:@"12-876-65433"] forKey:@"PhoneNo"];
[tableDataArray addObject:dict4];

NSMutableDictionary *dict5 = [[NSMutableDictionary alloc] init];
[dict5 setObject:[NSString stringWithFormat:@"Clark Kristan"] forKey:@"Name"];
[dict5 setObject:[NSString stringWithFormat:@"Contact Person"] forKey:@"Position"];
[dict5 setObject:[NSString stringWithFormat:@"[email protected]"] forKey:@"Email"];
[dict5 setObject:[NSString stringWithFormat:@"65-876-65433"] forKey:@"PhoneNo"];
[tableDataArray addObject:dict5];

所以，我想创建索引 UITableView。我的 UITableView 委托和数据源方法与上述各自的数据格式将如何？

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section{
}

- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section{
}

- (NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView {
}

- (NSInteger)tableView:(UITableView *)tableView sectionForSectionIndexTitle:(NSString *)title atIndex:(NSInteger)index {
}

谢谢

Answer 1

您需要创建一个要在索引列表中显示的标题数组，并在 (NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView { } 和此 (NSInteger) 中返回该数组)tableView:(UITableView *)tableView sectionForSectionIndexTitle:(NSString *)title atIndex:(NSInteger)index { } 只需返回索引。

了解更多信息请阅读 apples文档-
http://developer.apple.com/库/ios/#documentation/uikit/reference/UITableViewDataSource_Protocol/Reference/Reference.html

Answer 2

有一篇关于 UITableView 索引的非常精彩的文章。

这是它的链接。

http://www.iphonedevcentral.com/indexed-uitableview-tutorial/