正则表达式替换为 sed
我正在 PHP 文件中进行替换，并且需要使用 sed 更改语言变量。这是我的工作代码：
sed -i '' -e "s/\$config\['language'\] = \"english\";/\$config['language'] = '$LANGUAGE';/" Sources/$APP/application/config/config.php
这无法匹配任何语言集：
sed -i '' -e "s/\$config\['language'\] = \"*\";/\$config['language'] = '$LANGUAGE';/" Sources/$APP/application/config/config.php
出了什么问题？
I'm making replacments in PHP file and I need to change the language variable with sed. Here my WORKING code:
sed -i '' -e "s/\$config\['language'\] = \"english\";/\$config['language'] = '$LANGUAGE';/" Sources/$APP/application/config/config.php
This is not working to match any language set:
sed -i '' -e "s/\$config\['language'\] = \"*\";/\$config['language'] = '$LANGUAGE';/" Sources/$APP/application/config/config.php
What's wrong?
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在
sed中，星号 (*) 字符表示“重复前一操作 0 次或多次”。这与外壳形成鲜明对比，外壳可以扩展到任何东西。你想要做的就是在星号之前添加一个.（意思是“任何东西”），如下所示：然后这将告诉你的程序“重复任何字符（
.) 任意次数 (*)”。In
sed, the asterisk (*) character denotes "repeat the previous thing 0 or more times." This is in contrast to a shell, where it expands to anything. What you want to do is shove a.(which means "anything"), right before the asterisk, like so:That will then tell your program "repeat any character (
.) any number of times (*)".那是因为
*并没有按照您的想法进行操作。在sed正则表达式中，与所有正则表达式一样，使用.*?表示任何字符集合（换行符除外）。这是因为.表示匹配任何内容一次，而*表示匹配前一项任意多次。?使其成为非贪婪的，这意味着只要表达式的其余部分匹配，它就会匹配尽可能少的字符。我不知道你输入的是什么，所以我无法判断你是否需要问号，安全总比抱歉好。That's because
*doesn't do what you think it does. In asedregular expression, as in all regular expressions, use.*?to mean any collection of characters (except newlines). That is because.means match anything once and*means match the previous item any number of times. The?makes it non-greedy, meaning it will match as few characters as possible as long as the rest of the expression matches. I don't know what you input is so I can't tell if you need the question mark, better safe than sorry.您需要将表达式中的
*替换为.*。*表示“前一项的 0 个或多个实例”（在本例中为"），因此您需要首先匹配.（任何字符），然后声明您想要 0 个或多个 that 实例。You need to replace the
*in the expression with.*.*means "0 or more instances of the previous item" (in this case the"), so you want to first match.(any character), then state you want 0 or more instances of that.