匹配类似之前出现的内容

发布于 2024-12-21 21:50:54 字数 281 浏览 0 评论 0原文

我需要制作一个正则表达式来匹配标签之间的内容，如下所示：

<tag>
    <b> Match Me </b>
</other-closing-tag>

它应该仅匹配同一标签之间的内容。所以结果应该是这样的：

1 match:
<b> Match Me </b>
Match me

我需要用 PHP 来做，但我不认为这那么重要......

原文

I need to make a regex which matches content between tags like this:

<tag>
    <b> Match Me </b>
</other-closing-tag>

It should match only the content between the same tag. So the result should be something like this:

1 match:
<b> Match Me </b>
Match me

And I need to do it in PHP, but I don't think that this is that important...

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信仰 2024-12-28 21:50:54

使用正则表达式反向引用，您可以在以下链接中阅读更多信息。

PHP：反向引用 - 手册

虽然使用常规解析 html-表达式从来都不是一个好主意，但我会假装您将使用此信息来解决完全不同的问题。 ;-)

示例片段

在下面，我们说结束标签的内容应该与我们的第一组 ([^>]+) 匹配的内容相同，通过使用 < code>\1 在我们的结束标签内。

$data =<<<EOT
  <awesome-tag> match-me </awesome-tag>
  <error-tag>   match-me </err0r-tag>
  <super-tag>   match-me </super-tag>
  <error-tag>   match-me </err0r-tag>
  <awesome-tag> match-me </awesome-tag>
EOT;

preg_match_all ('/<([^>]+)>.*?match-me.*?<\/\1>/s', $data, $matches);

print_r ($matches);

输出

Array
(
  [0] => Array
  (
    [0] => <awesome-tag> match-me </awesome-tag>
    [1] => <super-tag>   match-me </super-tag>
    [2] => <awesome-tag> match-me </awesome-tag>
  )

  [1] => Array
  (
    [0] => awesome-tag
    [1] => super-tag
    [2] => awesome-tag
  )
)

Use regular expression back references, which you can read more about under the following link.

PHP: Back references - Manual

Though parsing html with regular-expressions is never a good idea, but I'm going to pretend that you are going to use this information for a completely different problem. ;-)

Example snippet

In the below we are saying that the contents of our end-tag should be the same as what is matched by our first group ([^>]+), by using \1 inside our closing tag.

$data =<<<EOT
  <awesome-tag> match-me </awesome-tag>
  <error-tag>   match-me </err0r-tag>
  <super-tag>   match-me </super-tag>
  <error-tag>   match-me </err0r-tag>
  <awesome-tag> match-me </awesome-tag>
EOT;

preg_match_all ('/<([^>]+)>.*?match-me.*?<\/\1>/s', $data, $matches);

print_r ($matches);

output

Array
(
  [0] => Array
  (
    [0] => <awesome-tag> match-me </awesome-tag>
    [1] => <super-tag>   match-me </super-tag>
    [2] => <awesome-tag> match-me </awesome-tag>
  )

  [1] => Array
  (
    [0] => awesome-tag
    [1] => super-tag
    [2] => awesome-tag
  )
)

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