从字符串中剥离外括号
我在编写从字符串中去除外括号的正则表达式时遇到一些麻烦（我想确保保留单/双引号内的任何括号）：
((0)) becomes 0
(0) becomes 0
('(0845) 187 1262') becomes '(0845) 187 1262'
我有两个正则表达式来匹配左右手外括号：
^[\(]* -- matches out the left outer brackets
[\)]*$ -- matches out the right outer brackets
是吗？可以将两者组合成一个正则表达式吗？
I am having some trouble writing a regex expression that will strip outer brackets from a string (I want to ensure any brackets within single/double quotes are preserved):
((0)) becomes 0
(0) becomes 0
('(0845) 187 1262') becomes '(0845) 187 1262'
I have got two regexes to match the left and right hand outer brackets:
^[\(]* -- matches out the left outer brackets
[\)]*$ -- matches out the right outer brackets
Is it possible to combine both into a single regex?
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是的，这一点也不困难，并且您的正则表达式也可以简化，因为您不需要字符类：
Yes, it's not at all difficult, and your regex can be simplified as well, as you don't need character classes: